{"id":2168,"date":"2026-04-03T20:05:59","date_gmt":"2026-04-03T20:05:59","guid":{"rendered":"https:\/\/rumahpintar.co.id\/blog\/?p=2168"},"modified":"2026-04-09T04:42:47","modified_gmt":"2026-04-09T04:42:47","slug":"15-contoh-soal-transformasi-tunggal-refleksi-translasi-rotasi-dilatasi","status":"publish","type":"post","link":"https:\/\/rumahpintar.co.id\/blog\/15-contoh-soal-transformasi-tunggal-refleksi-translasi-rotasi-dilatasi\/","title":{"rendered":"15 Contoh Soal Transformasi Tunggal (Refleksi, Translasi, Rotasi, Dilatasi) & Pembahasan TKA Matematika SMP"},"content":{"rendered":"

Bimbel Rumah Pintar<\/strong><\/a> – Soal <\/span>transformasi tunggal pada bahasan geometri adalah perubahan posisi atau ukuran suatu titik, garis, atau bangun datar pada bidang. Prinsip dasar yang harus dikuasai adalah empat jenis transformasi tunggal: translasi<\/strong>\u00a0(pergeseran sejauh vektor tertentu),\u00a0refleksi<\/strong>\u00a0(pencerminan terhadap sumbu atau garis),\u00a0rotasi<\/strong>\u00a0(perputaran dengan pusat dan sudut tertentu), dan\u00a0dilatasi<\/strong>\u00a0(perkalian ukuran dengan faktor skala tertentu).<\/p>\n

Mengapa latihan soal transformasi geometri sangat penting?<\/strong>\u00a0Soal TKA Matematika SMP sering menyajikan masalah kontekstual seperti pergerakan robot pembersih, transformasi segitiga pada bidang koordinat, atau menentukan jenis transformasi yang tepat dari gambar.<\/p>\n

Tanpa latihan yang cukup, siswa sering tertukar arah rotasi (90\u00b0 berlawanan vs searah jarum jam), lupa tanda negatif pada refleksi terhadap sumbu X atau Y, atau keliru dalam menerapkan rumus dilatasi. Dengan menguasai 15 variasi soal berikut (dengan konsep sama tetapi angka dan konteks berbeda dari contoh sebelumnya), Sahabat Rumah Pintar akan mampu menentukan posisi akhir bangun setelah ditransformasi, mengidentifikasi jenis transformasi dengan tepat, dan menjawab soal TKA dengan percaya diri.<\/p>\n

\n

15 Contoh Soal dan Pembahasan Transformasi Tunggal<\/h2>\n
\n

Soal 1 (Translasi Robot \u2013 Tipe TKA)<\/h3>\n

Sebuah robot pembersih berada di posisi awal (5, -3). Robot bergerak mengikuti translasi\u00a0T(3,\u22124)<\/span>T<\/span>(<\/span>3<\/span>,<\/span>\u2212<\/span>4<\/span>)<\/span><\/span><\/span><\/span>. Tentukan posisi akhir robot!<\/p>\n

Pembahasan:<\/strong><\/p>\n

    \n
  • \n

    Translasi:\u00a0(x,y)\u2192(x+a,y+b)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>x<\/span>+<\/span><\/span>a<\/span>,<\/span>y<\/span>+<\/span><\/span>b<\/span>)<\/span><\/span><\/span><\/span>\u00a0dengan\u00a0T(a,b)<\/span>T<\/span>(<\/span>a<\/span>,<\/span>b<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

  • \n

    x\u2032=5+3=8<\/span>x<\/span>\u2032<\/span><\/span><\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>5<\/span>+<\/span><\/span>3<\/span>=<\/span><\/span>8<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

  • \n

    y\u2032=\u22123+(\u22124)=\u22127<\/span>y<\/span>\u2032<\/span><\/span><\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>\u2212<\/span>3<\/span>+<\/span><\/span>(<\/span>\u2212<\/span>4<\/span>)<\/span>=<\/span><\/span>\u2212<\/span>7<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

  • \n

    Posisi akhir =\u00a0(8,\u22127)<\/span>(<\/span>8<\/span>,<\/span>\u2212<\/span>7<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

    Jawaban: (8, -7)<\/strong><\/p>\n

    \n

    Soal 2 (Translasi \u2013 Menentukan Vektor dari Posisi Awal dan Akhir)<\/h3>\n

    Sebuah titik bergerak dari posisi P(2, 5) ke posisi P'(9, 1). Tentukan vektor translasi yang digunakan!<\/p>\n

    Pembahasan:<\/strong><\/p>\n

      \n
    • \n

      Vektor translasi =\u00a0(x\u2032\u2212x,y\u2032\u2212y)<\/span>(<\/span>x<\/span>\u2032<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>x<\/span>,<\/span>y<\/span>\u2032<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>y<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

    • \n

      =(9\u22122,1\u22125)=(7,\u22124)<\/span>=<\/span><\/span>(<\/span>9<\/span>\u2212<\/span><\/span>2<\/span>,<\/span>1<\/span>\u2212<\/span><\/span>5<\/span>)<\/span>=<\/span><\/span>(<\/span>7<\/span>,<\/span>\u2212<\/span>4<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

      Jawaban:\u00a0T(7,\u22124)<\/span>T<\/span>(<\/span>7<\/span>,<\/span>\u2212<\/span>4<\/span>)<\/span><\/span><\/span><\/span><\/strong><\/p>\n

      \n

      Soal 3 (Refleksi terhadap Sumbu X)<\/h3>\n

      Titik Q(6, -8) dicerminkan terhadap sumbu X. Tentukan bayangan Q’!<\/p>\n

      Pembahasan:<\/strong><\/p>\n

        \n
      • \n

        Refleksi sumbu X:\u00a0(x,y)\u2192(x,\u2212y)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>x<\/span>,<\/span>\u2212<\/span>y<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

      • \n

        Q’ =\u00a0(6,\u2212(\u22128))=(6,8)<\/span>(<\/span>6<\/span>,<\/span>\u2212<\/span>(<\/span>\u2212<\/span>8<\/span>))<\/span>=<\/span><\/span>(<\/span>6<\/span>,<\/span>8<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

        Jawaban: (6, 8)<\/strong><\/p>\n

        \n

        Soal 4 (Refleksi terhadap Sumbu Y)<\/h3>\n

        Titik R(-4, 7) dicerminkan terhadap sumbu Y. Tentukan bayangan R’!<\/p>\n

        Pembahasan:<\/strong><\/p>\n

          \n
        • \n

          Refleksi sumbu Y:\u00a0(x,y)\u2192(\u2212x,y)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>\u2212<\/span>x<\/span>,<\/span>y<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

        • \n

          R’ =\u00a0(\u2212(\u22124),7)=(4,7)<\/span>(<\/span>\u2212<\/span>(<\/span>\u2212<\/span>4<\/span>)<\/span>,<\/span>7<\/span>)<\/span>=<\/span><\/span>(<\/span>4<\/span>,<\/span>7<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

          Jawaban: (4, 7)<\/strong><\/p>\n

          \n

          Soal 5 (Refleksi terhadap Garis y = x)<\/h3>\n

          Titik S(5, 9) dicerminkan terhadap garis y = x. Tentukan bayangan S’!<\/p>\n

          Pembahasan:<\/strong><\/p>\n

            \n
          • \n

            Refleksi y = x:\u00a0(x,y)\u2192(y,x)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>y<\/span>,<\/span>x<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

          • \n

            S’ =\u00a0(9,5)<\/span>(<\/span>9<\/span>,<\/span>5<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

            Jawaban: (9, 5)<\/strong><\/p>\n

            \n

            Soal 6 (Refleksi terhadap Garis y = -x)<\/h3>\n

            Titik T(7, 2) dicerminkan terhadap garis y = -x. Tentukan bayangan T’!<\/p>\n

            Pembahasan:<\/strong><\/p>\n

              \n
            • \n

              Refleksi y = -x:\u00a0(x,y)\u2192(\u2212y,\u2212x)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>\u2212<\/span>y<\/span>,<\/span>\u2212<\/span>x<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

            • \n

              T’ =\u00a0(\u22122,\u22127)<\/span>(<\/span>\u2212<\/span>2<\/span>,<\/span>\u2212<\/span>7<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

              Jawaban: (-2, -7)<\/strong><\/p>\n

              \n

              Soal 7 (Rotasi 90\u00b0 Berlawanan Arah Jarum Jam)<\/h3>\n

              Titik U(3, 6) dirotasi 90\u00b0 berlawanan arah jarum jam dengan pusat O(0,0). Tentukan bayangan U’!<\/p>\n

              Pembahasan:<\/strong><\/p>\n

                \n
              • \n

                Rotasi 90\u00b0 berlawanan:\u00a0(x,y)\u2192(\u2212y,x)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>\u2212<\/span>y<\/span>,<\/span>x<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

              • \n

                U’ =\u00a0(\u22126,3)<\/span>(<\/span>\u2212<\/span>6<\/span>,<\/span>3<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                Jawaban: (-6, 3)<\/strong><\/p>\n

                \n

                Soal 8 (Rotasi 90\u00b0 Searah Jarum Jam)<\/h3>\n

                Titik V(8, -2) dirotasi 90\u00b0 searah jarum jam dengan pusat O(0,0). Tentukan bayangan V’!<\/p>\n

                Pembahasan:<\/strong><\/p>\n

                  \n
                • \n

                  Rotasi 90\u00b0 searah:\u00a0(x,y)\u2192(y,\u2212x)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>y<\/span>,<\/span>\u2212<\/span>x<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                • \n

                  V’ =\u00a0(\u22122,\u22128)<\/span>(<\/span>\u2212<\/span>2<\/span>,<\/span>\u2212<\/span>8<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                  Jawaban: (-2, -8)<\/strong><\/p>\n

                  \n

                  Soal 9 (Rotasi 180\u00b0)<\/h3>\n

                  Titik W(-5, 4) dirotasi 180\u00b0 dengan pusat O(0,0). Tentukan bayangan W’!<\/p>\n

                  Pembahasan:<\/strong><\/p>\n

                    \n
                  • \n

                    Rotasi 180\u00b0:\u00a0(x,y)\u2192(\u2212x,\u2212y)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>\u2212<\/span>x<\/span>,<\/span>\u2212<\/span>y<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                  • \n

                    W’ =\u00a0(5,\u22124)<\/span>(<\/span>5<\/span>,<\/span>\u2212<\/span>4<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                    Jawaban: (5, -4)<\/strong><\/p>\n

                    \n

                    Soal 10 (Rotasi 270\u00b0 Berlawanan Arah Jarum Jam)<\/h3>\n

                    Titik X(4, 7) dirotasi 270\u00b0 berlawanan arah jarum jam dengan pusat O(0,0). Tentukan bayangan X’!<\/p>\n

                    Pembahasan:<\/strong><\/p>\n

                      \n
                    • \n

                      Rotasi 270\u00b0 berlawanan = rotasi 90\u00b0 searah:\u00a0(x,y)\u2192(y,\u2212x)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>y<\/span>,<\/span>\u2212<\/span>x<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                    • \n

                      X’ =\u00a0(7,\u22124)<\/span>(<\/span>7<\/span>,<\/span>\u2212<\/span>4<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                      Jawaban: (7, -4)<\/strong><\/p>\n

                      \n

                      Soal 11 (Dilatasi dengan Faktor Skala > 1)<\/h3>\n

                      Titik Y(5, 8) didilatasi dengan pusat O(0,0) dan faktor skala 3. Tentukan bayangan Y’!<\/p>\n

                      Pembahasan:<\/strong><\/p>\n

                        \n
                      • \n

                        Dilatasi:\u00a0(x,y)\u2192(kx,ky)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>k<\/span>x<\/span>,<\/span>k<\/span>y<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                      • \n

                        Y’ =\u00a0(3\u00d75,3\u00d78)=(15,24)<\/span>(<\/span>3<\/span>\u00d7<\/span><\/span>5<\/span>,<\/span>3<\/span>\u00d7<\/span><\/span>8<\/span>)<\/span>=<\/span><\/span>(<\/span>15<\/span>,<\/span>24<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                        Jawaban: (15, 24)<\/strong><\/p>\n

                        \n

                        Soal 12 (Dilatasi dengan Faktor Skala 0 < k < 1)<\/h3>\n

                        Titik Z(18, 24) didilatasi dengan pusat O(0,0) dan faktor skala\u00a013<\/span>3<\/span><\/span>1<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>. Tentukan bayangan Z’!<\/p>\n

                        Pembahasan:<\/strong><\/p>\n

                          \n
                        • \n

                          Z’ =\u00a0(13\u00d718,13\u00d724)=(6,8)<\/span>(<\/span>3<\/span><\/span>1<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u00d7<\/span><\/span>18<\/span>,<\/span>3<\/span><\/span>1<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u00d7<\/span><\/span>24<\/span>)<\/span>=<\/span><\/span>(<\/span>6<\/span>,<\/span>8<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                          Jawaban: (6, 8)<\/strong><\/p>\n

                          \n

                          Soal 13 (Menentukan Jenis Transformasi dari Segitiga \u2013 Tipe TKA)<\/h3>\n

                          Segitiga ABC dengan titik A(2, 1), B(5, 1), C(3, 4) ditransformasi menjadi segitiga A’B’C’ dengan A'( -1, 2), B'(-1, 5), C'(-4, 3). Transformasi apa yang terjadi?<\/p>\n

                          Pembahasan:<\/strong><\/p>\n

                            \n
                          • \n

                            Perhatikan perubahan A(2,1) \u2192 A'(-1,2)<\/p>\n<\/li>\n

                          • \n

                            Pola:\u00a0(x,y)\u2192(\u2212y,x)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>\u2212<\/span>y<\/span>,<\/span>x<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                          • \n

                            Ini adalah rumus rotasi 90\u00b0 berlawanan arah jarum jam<\/p>\n<\/li>\n

                          • \n

                            Cek B(5,1) \u2192 (-1,5) \u2713, C(3,4) \u2192 (-4,3) \u2713<\/p>\n<\/li>\n<\/ul>\n

                            Jawaban: Rotasi 90\u00b0 berlawanan arah jarum jam dengan pusat O(0,0)<\/strong><\/p>\n

                            \n

                            Soal 14 (Komposisi Transformasi Sederhana \u2013 Translasi lalu Refleksi)<\/h3>\n

                            Titik P(4, 5) ditranslasi oleh\u00a0T(\u22123,2)<\/span>T<\/span>(<\/span>\u2212<\/span>3<\/span>,<\/span>2<\/span>)<\/span><\/span><\/span><\/span>, lalu direfleksikan terhadap sumbu X. Tentukan bayangan akhir!<\/p>\n

                            Pembahasan:<\/strong><\/p>\n

                              \n
                            • \n

                              Translasi: P'(4-3, 5+2) = (1, 7)<\/p>\n<\/li>\n

                            • \n

                              Refleksi sumbu X: P”(1, -7)<\/p>\n<\/li>\n<\/ul>\n

                              Jawaban: (1, -7)<\/strong><\/p>\n

                              \n

                              Soal 15 (Komposisi Transformasi \u2013 Rotasi lalu Dilatasi)<\/h3>\n

                              Titik Q(3, 4) dirotasi 90\u00b0 searah jarum jam, lalu didilatasi dengan faktor skala 2 dengan pusat O(0,0). Tentukan bayangan akhir!<\/p>\n

                              Pembahasan:<\/strong><\/p>\n

                                \n
                              • \n

                                Rotasi 90\u00b0 searah:\u00a0(x,y)\u2192(y,\u2212x)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>y<\/span>,<\/span>\u2212<\/span>x<\/span>)<\/span><\/span><\/span><\/span>\u00a0\u2192 Q'(4, -3)<\/p>\n<\/li>\n

                              • \n

                                Dilatasi faktor skala 2: Q”(2\u00d74, 2\u00d7(-3)) = (8, -6)<\/p>\n<\/li>\n<\/ul>\n

                                Jawaban: (8, -6)<\/strong><\/p>\n

                                \n

                                Ringkasan Rumus Penting Transformasi Geometri<\/h2>\n
                                \n
                                \n
                                <\/div>\n
                                <\/div>\n<\/div>\n\n\n\n\n\n\n\n\n\n\n\n\n\n
                                Transformasi<\/th>\nRumus<\/th>\nContoh (2,3) menjadi<\/th>\n<\/tr>\n<\/thead>\n
                                Translasi\u00a0T(a,b)<\/span>T<\/span>(<\/span>a<\/span>,<\/span>b<\/span>)<\/span><\/span><\/span><\/span><\/strong><\/td>\n(x,y)\u2192(x+a,y+b)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>x<\/span>+<\/span><\/span>a<\/span>,<\/span>y<\/span>+<\/span><\/span>b<\/span>)<\/span><\/span><\/span><\/span><\/td>\nT(4,\u22122)<\/span>T<\/span>(<\/span>4<\/span>,<\/span>\u2212<\/span>2<\/span>)<\/span><\/span><\/span><\/span>\u00a0\u2192 (6,1)<\/td>\n<\/tr>\n
                                Refleksi sumbu X<\/strong><\/td>\n(x,y)\u2192(x,\u2212y)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>x<\/span>,<\/span>\u2212<\/span>y<\/span>)<\/span><\/span><\/span><\/span><\/td>\n(2, -3)<\/td>\n<\/tr>\n
                                Refleksi sumbu Y<\/strong><\/td>\n(x,y)\u2192(\u2212x,y)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>\u2212<\/span>x<\/span>,<\/span>y<\/span>)<\/span><\/span><\/span><\/span><\/td>\n(-2, 3)<\/td>\n<\/tr>\n
                                Refleksi y = x<\/strong><\/td>\n(x,y)\u2192(y,x)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>y<\/span>,<\/span>x<\/span>)<\/span><\/span><\/span><\/span><\/td>\n(3, 2)<\/td>\n<\/tr>\n
                                Refleksi y = -x<\/strong><\/td>\n(x,y)\u2192(\u2212y,\u2212x)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>\u2212<\/span>y<\/span>,<\/span>\u2212<\/span>x<\/span>)<\/span><\/span><\/span><\/span><\/td>\n(-3, -2)<\/td>\n<\/tr>\n
                                Rotasi 90\u00b0 berlawanan<\/strong><\/td>\n(x,y)\u2192(\u2212y,x)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>\u2212<\/span>y<\/span>,<\/span>x<\/span>)<\/span><\/span><\/span><\/span><\/td>\n(-3, 2)<\/td>\n<\/tr>\n
                                Rotasi 90\u00b0 searah<\/strong><\/td>\n(x,y)\u2192(y,\u2212x)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>y<\/span>,<\/span>\u2212<\/span>x<\/span>)<\/span><\/span><\/span><\/span><\/td>\n(3, -2)<\/td>\n<\/tr>\n
                                Rotasi 180\u00b0<\/strong><\/td>\n(x,y)\u2192(\u2212x,\u2212y)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>\u2212<\/span>x<\/span>,<\/span>\u2212<\/span>y<\/span>)<\/span><\/span><\/span><\/span><\/td>\n(-2, -3)<\/td>\n<\/tr>\n
                                Dilatasi skala\u00a0k<\/span>k<\/span><\/span><\/span><\/span><\/strong><\/td>\n(x,y)\u2192(kx,ky)<\/span>(<\/span>x<\/span>,<\/span>y<\/span>)<\/span>\u2192<\/span><\/span>(<\/span>k<\/span>x<\/span>,<\/span>k<\/span>y<\/span>)<\/span><\/span><\/span><\/span><\/td>\nk=2<\/span>k<\/span>=<\/span><\/span>2<\/span><\/span><\/span><\/span>\u00a0\u2192 (4,6)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

                                Tips Cepat Mengenali Transformasi:<\/strong><\/p>\n

                                  \n
                                • \n

                                  Semua titik bergeser dengan vektor sama \u2192\u00a0Translasi<\/strong><\/p>\n<\/li>\n

                                • \n

                                  x berubah tanda, y tetap \u2192\u00a0Refleksi sumbu Y<\/strong><\/p>\n<\/li>\n

                                • \n

                                  y berubah tanda, x tetap \u2192\u00a0Refleksi sumbu X<\/strong><\/p>\n<\/li>\n

                                • \n

                                  (x,y) \u2192 (y,x) \u2192\u00a0Refleksi y = x<\/strong><\/p>\n<\/li>\n

                                • \n

                                  (x,y) \u2192 (-y, x) \u2192\u00a0Rotasi 90\u00b0 berlawanan<\/strong><\/p>\n<\/li>\n

                                • \n

                                  (x,y) \u2192 (y, -x) \u2192\u00a0Rotasi 90\u00b0 searah<\/strong><\/p>\n<\/li>\n

                                • \n

                                  (x,y) \u2192 (-x, -y) \u2192\u00a0Rotasi 180\u00b0<\/strong>\u00a0atau\u00a0Refleksi titik asal<\/strong><\/p>\n<\/li>\n

                                • \n

                                  (x,y) \u2192 (kx, ky) \u2192\u00a0Dilatasi<\/strong><\/p>\n<\/li>\n<\/ul>\n

                                  \n

                                  Sahabat Rumah Pintar<\/strong>, dengan menguasai 15 soal di atas, kalian sudah siap menentukan posisi akhir setelah transformasi, mengidentifikasi jenis transformasi dari perubahan koordinat, dan menyelesaikan soal cerita transformasi di TKA Matematika SMP. Ingat kuncinya:\u00a0hafalkan rumus setiap transformasi, perhatikan arah rotasi dengan teliti, dan jangan lupa tanda negatif pada refleksi<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"

                                  Bimbel Rumah Pintar – Soal transformasi tunggal pada bahasan geometri adalah perubahan posisi atau ukuran suatu titik, garis, atau bangun datar pada bidang. Prinsip dasar yang harus dikuasai adalah empat jenis transformasi tunggal: translasi\u00a0(pergeseran sejauh vektor tertentu),\u00a0refleksi\u00a0(pencerminan terhadap sumbu atau […]<\/p>\n","protected":false},"author":1,"featured_media":2171,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"set","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[4],"tags":[224],"class_list":["post-2168","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-bahas-soal","tag-soal-tka-matematika-smp"],"_links":{"self":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2168","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/comments?post=2168"}],"version-history":[{"count":1,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2168\/revisions"}],"predecessor-version":[{"id":2172,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2168\/revisions\/2172"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/media\/2171"}],"wp:attachment":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/media?parent=2168"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/categories?post=2168"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/tags?post=2168"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}