{"id":2129,"date":"2026-04-03T16:10:17","date_gmt":"2026-04-03T16:10:17","guid":{"rendered":"https:\/\/rumahpintar.co.id\/blog\/?p=2129"},"modified":"2026-04-08T19:29:32","modified_gmt":"2026-04-08T19:29:32","slug":"15-contoh-soal-barisan-berhingga-bilangan","status":"publish","type":"post","link":"https:\/\/rumahpintar.co.id\/blog\/15-contoh-soal-barisan-berhingga-bilangan\/","title":{"rendered":"15 Contoh Soal Barisan Berhingga Bilangan dan Pola Bilangan di TKA Matematika SMP"},"content":{"rendered":"

Bimbel Rumah Pintar<\/strong><\/a> – <\/b>Soal barisan berhingga bilangan adalah urutan bilangan yang memiliki jumlah suku terbatas dengan pola atau aturan tertentu yang konsisten. Prinsip dasar yang harus dikuasai adalah kemampuan mengamati pola dari suku-suku yang diberikan.<\/p>\n

Kemudian mengidentifikasi jenis barisan tersebut apakah termasuk barisan aritmetika<\/strong>\u00a0(selisih antar suku tetap),\u00a0barisan geometri<\/strong>\u00a0(rasio antar suku tetap), atau\u00a0pola bilangan khusus<\/strong>\u00a0seperti pola persegi (Un=n2<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>n<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>), pola segitiga (Un=n(n+1)2<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span><\/span>n<\/span>(<\/span>n<\/span>+<\/span>1)<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>), pola ganjil (Un=2n\u22121<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span>n<\/span>\u2212<\/span><\/span>1<\/span><\/span><\/span><\/span>), dan pola genap (Un=2n<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span>n<\/span><\/span><\/span><\/span>). Kunci keberhasilan terletak pada ketelitian dalam menghitung beda atau rasio, serta kemampuan mengenali pola bertingkat ketika selisih antar suku tidak langsung tetap.<\/p>\n

Mengapa latihan soal barisan bilangan sangat penting?<\/strong>\u00a0Soal TKA Matematika SMP hampir selalu menghadirkan barisan bilangan dalam berbagai bentuk, mulai dari menentukan suku ke-n barisan aritmetika\/geometri, menghitung jumlah titik pada pola ke-n dari susunan gambar, hingga soal cerita kontekstual seperti pertumbuhan bakteri, kenaikan gaji, atau tabungan dengan kenaikan tetap.<\/p>\n

Tanpa latihan yang cukup, siswa sering keliru dalam menentukan beda (lupa rumus Un=a+(n\u22121)b<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>+<\/span><\/span>(<\/span>n<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>b<\/span><\/span><\/span><\/span>), salah menghitung rasio pada barisan geometri, atau tidak mengenali pola bilangan segitiga dan persegi. Dengan menguasai 15 variasi soal berikut, Sahabat Rumah Pintar akan mampu menganalisis pola bilangan dengan cepat, menentukan suku ke-n dengan tepat, dan menjawab soal TKA dengan percaya diri.<\/p>\n

\n

15 Contoh Soal dan Pembahasan Barisan Berhingga Bilangan<\/h2>\n
\n

Soal 1 (Pola Titik \u2013 Bilangan Segitiga)<\/h3>\n

Perhatikan susunan titik berikut!<\/p>\n

    \n
  • \n

    Pola ke-1: 1 titik<\/p>\n<\/li>\n

  • \n

    Pola ke-2: 3 titik<\/p>\n<\/li>\n

  • \n

    Pola ke-3: 6 titik<\/p>\n<\/li>\n

  • \n

    Pola ke-4: 10 titik<\/p>\n<\/li>\n<\/ul>\n

    Jika pola tersebut berlanjut, maka jumlah titik pada pola ke-6 adalah ….<\/p>\n

    Pembahasan:<\/strong><\/p>\n

      \n
    • \n

      Pola: 1, 3, 6, 10, …<\/p>\n<\/li>\n

    • \n

      Selisih: 2, 3, 4, … (bukan aritmetika biasa, ini aritmetika tingkat 2)<\/p>\n<\/li>\n

    • \n

      Ini adalah pola bilangan segitiga:\u00a0Un=n(n+1)2<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span><\/span>n<\/span>(<\/span>n<\/span>+<\/span>1)<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

    • \n

      U6=6\u00d772=422=21<\/span>U<\/span>6<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span><\/span>6\u00d7<\/span>7<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span><\/span>42<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>21<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

      Jawaban: 21 titik<\/strong><\/p>\n

      \n

      Soal 2 (Barisan Aritmetika \u2013 Menentukan Suku ke-n)<\/h3>\n

      Diketahui barisan aritmetika: 7, 12, 17, 22, … Tentukan suku ke-15!<\/p>\n

      Pembahasan:<\/strong><\/p>\n

        \n
      • \n

        a=7<\/span>a<\/span>=<\/span><\/span>7<\/span><\/span><\/span><\/span>,\u00a0b=12\u22127=5<\/span>b<\/span>=<\/span><\/span>12<\/span>\u2212<\/span><\/span>7<\/span>=<\/span><\/span>5<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

      • \n

        Un=a+(n\u22121)b<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>+<\/span><\/span>(<\/span>n<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>b<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

      • \n

        U15=7+(15\u22121)\u00d75=7+14\u00d75=7+70=77<\/span>U<\/span>15<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>7<\/span>+<\/span><\/span>(<\/span>15<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>\u00d7<\/span><\/span>5<\/span>=<\/span><\/span>7<\/span>+<\/span><\/span>14<\/span>\u00d7<\/span><\/span>5<\/span>=<\/span><\/span>7<\/span>+<\/span><\/span>70<\/span>=<\/span><\/span>77<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

        Jawaban: 77<\/strong><\/p>\n

        \n

        Soal 3 (Barisan Geometri \u2013 Menentukan Suku ke-n)<\/h3>\n

        Diketahui barisan geometri: 3, 6, 12, 24, … Tentukan suku ke-8!<\/p>\n

        Pembahasan:<\/strong><\/p>\n

          \n
        • \n

          a=3<\/span>a<\/span>=<\/span><\/span>3<\/span><\/span><\/span><\/span>,\u00a0r=6\u00f73=2<\/span>r<\/span>=<\/span><\/span>6<\/span>\u00f7<\/span><\/span>3<\/span>=<\/span><\/span>2<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

        • \n

          Un=a\u00d7rn\u22121<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>\u00d7<\/span><\/span>r<\/span>n<\/span>\u2212<\/span>1<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

        • \n

          U8=3\u00d727=3\u00d7128=384<\/span>U<\/span>8<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>3<\/span>\u00d7<\/span><\/span>27<\/span><\/span><\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>3<\/span>\u00d7<\/span><\/span>128<\/span>=<\/span><\/span>384<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

          Jawaban: 384<\/strong><\/p>\n

          \n

          Soal 4 (Pola Batang Korek Api \u2013 Barisan Aritmetika)<\/h3>\n

          Perhatikan pola batang korek api berikut:<\/p>\n

            \n
          • \n

            Pola 1: 4 batang (persegi)<\/p>\n<\/li>\n

          • \n

            Pola 2: 7 batang<\/p>\n<\/li>\n

          • \n

            Pola 3: 10 batang<\/p>\n<\/li>\n<\/ul>\n

            Berapa batang korek api pada pola ke-10?<\/p>\n

            Pembahasan:<\/strong><\/p>\n

              \n
            • \n

              Barisan: 4, 7, 10, … \u2192 aritmetika<\/p>\n<\/li>\n

            • \n

              a=4<\/span>a<\/span>=<\/span><\/span>4<\/span><\/span><\/span><\/span>,\u00a0b=3<\/span>b<\/span>=<\/span><\/span>3<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

            • \n

              U10=4+(10\u22121)\u00d73=4+27=31<\/span>U<\/span>10<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>4<\/span>+<\/span><\/span>(<\/span>10<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>\u00d7<\/span><\/span>3<\/span>=<\/span><\/span>4<\/span>+<\/span><\/span>27<\/span>=<\/span><\/span>31<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

              Jawaban: 31 batang<\/strong><\/p>\n

              \n

              Soal 5 (Barisan Aritmetika Bertingkat)<\/h3>\n

              Diketahui barisan: 2, 5, 10, 17, … Tentukan suku ke-8!<\/p>\n

              Pembahasan:<\/strong><\/p>\n

                \n
              • \n

                Selisih tingkat 1: 3, 5, 7, … (beda = 2) \u2192 aritmetika tingkat 2<\/p>\n<\/li>\n

              • \n

                Rumus pola:\u00a0Un=n2+1<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>n<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>1<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

              • \n

                U8=82+1=64+1=65<\/span>U<\/span>8<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>82<\/span><\/span><\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>1<\/span>=<\/span><\/span>64<\/span>+<\/span><\/span>1<\/span>=<\/span><\/span>65<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                Jawaban: 65<\/strong><\/p>\n

                \n

                Soal 6 (Soal Cerita \u2013 Kenaikan Gaji)<\/h3>\n

                Sebuah perusahaan memberikan kenaikan gaji tetap setiap bulan. Gaji bulan pertama Rp3.000.000, bulan kedua Rp3.200.000, bulan ketiga Rp3.400.000. Berapa gaji pada bulan ke-12?<\/p>\n

                Pembahasan:<\/strong><\/p>\n

                  \n
                • \n

                  a=3.000.000<\/span>a<\/span>=<\/span><\/span>3.000.000<\/span><\/span><\/span><\/span>,\u00a0b=200.000<\/span>b<\/span>=<\/span><\/span>200.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                • \n

                  U12=3.000.000+(12\u22121)\u00d7200.000<\/span>U<\/span>12<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>3.000.000<\/span>+<\/span><\/span>(<\/span>12<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>\u00d7<\/span><\/span>200.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                • \n

                  =3.000.000+11\u00d7200.000<\/span>=<\/span><\/span>3.000.000<\/span>+<\/span><\/span>11<\/span>\u00d7<\/span><\/span>200.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                • \n

                  =3.000.000+2.200.000=5.200.000<\/span>=<\/span><\/span>3.000.000<\/span>+<\/span><\/span>2.200.000<\/span>=<\/span><\/span>5.200.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                  Jawaban: Rp5.200.000<\/strong><\/p>\n

                  \n

                  Soal 7 (Soal Cerita \u2013 Pertumbuhan Bakteri)<\/h3>\n

                  Sebuah bakteri membelah diri menjadi 2 setiap 20 menit. Jika mula-mula ada 5 bakteri, berapa jumlah bakteri setelah 2 jam?<\/p>\n

                  Pembahasan:<\/strong><\/p>\n

                    \n
                  • \n

                    2 jam = 120 menit \u2192 120 \u00f7 20 = 6 kali pembelahan<\/p>\n<\/li>\n

                  • \n

                    a=5<\/span>a<\/span>=<\/span><\/span>5<\/span><\/span><\/span><\/span>,\u00a0r=2<\/span>r<\/span>=<\/span><\/span>2<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                  • \n

                    Setelah 6 kali pembelahan = suku ke-7<\/p>\n<\/li>\n

                  • \n

                    U7=5\u00d726=5\u00d764=320<\/span>U<\/span>7<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>5<\/span>\u00d7<\/span><\/span>26<\/span><\/span><\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>5<\/span>\u00d7<\/span><\/span>64<\/span>=<\/span><\/span>320<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                    Jawaban: 320 bakteri<\/strong><\/p>\n

                    \n

                    Soal 8 (Suku Tengah Barisan Aritmetika Berhingga)<\/h3>\n

                    Diketahui barisan aritmetika: 4, 9, 14, …, 74. Tentukan suku tengahnya!<\/p>\n

                    Pembahasan:<\/strong><\/p>\n

                      \n
                    • \n

                      a=4<\/span>a<\/span>=<\/span><\/span>4<\/span><\/span><\/span><\/span>,\u00a0b=5<\/span>b<\/span>=<\/span><\/span>5<\/span><\/span><\/span><\/span>,\u00a0Un=74<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>74<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                    • \n

                      Cari\u00a0n<\/span>n<\/span><\/span><\/span><\/span>:\u00a04+(n\u22121)5=74<\/span>4<\/span>+<\/span><\/span>(<\/span>n<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>5<\/span>=<\/span><\/span>74<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                    • \n

                      (n\u22121)5=70\u2192n\u22121=14\u2192n=15<\/span>(<\/span>n<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>5<\/span>=<\/span><\/span>70<\/span>\u2192<\/span><\/span>n<\/span>\u2212<\/span><\/span>1<\/span>=<\/span><\/span>14<\/span>\u2192<\/span><\/span>n<\/span>=<\/span><\/span>15<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                    • \n

                      Suku tengah (n ganjil) =\u00a0U8<\/span>U<\/span>8<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                    • \n

                      U8=4+7\u00d75=4+35=39<\/span>U<\/span>8<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>4<\/span>+<\/span><\/span>7<\/span>\u00d7<\/span><\/span>5<\/span>=<\/span><\/span>4<\/span>+<\/span><\/span>35<\/span>=<\/span><\/span>39<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                      Jawaban: 39<\/strong><\/p>\n

                      \n

                      Soal 9 (Pola Bilangan Persegi)<\/h3>\n

                      Tentukan suku ke-10 dari barisan: 1, 4, 9, 16, …<\/p>\n

                      Pembahasan:<\/strong><\/p>\n

                        \n
                      • \n

                        Pola persegi:\u00a0Un=n2<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>n<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                      • \n

                        U10=102=100<\/span>U<\/span>10<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>1<\/span>02<\/span><\/span><\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>100<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                        Jawaban: 100<\/strong><\/p>\n

                        \n

                        Soal 10 (Pola Bilangan Segitiga)<\/h3>\n

                        Tentukan suku ke-8 dari barisan: 1, 3, 6, 10, …<\/p>\n

                        Pembahasan:<\/strong><\/p>\n

                          \n
                        • \n

                          Pola segitiga:\u00a0Un=n(n+1)2<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span><\/span>n<\/span>(<\/span>n<\/span>+<\/span>1)<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                        • \n

                          U8=8\u00d792=722=36<\/span>U<\/span>8<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span><\/span>8\u00d7<\/span>9<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span><\/span>72<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>36<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                          Jawaban: 36<\/strong><\/p>\n

                          \n

                          Soal 11 (Pola Bilangan Ganjil)<\/h3>\n

                          Tentukan suku ke-15 dari barisan: 1, 3, 5, 7, …<\/p>\n

                          Pembahasan:<\/strong><\/p>\n

                            \n
                          • \n

                            Pola ganjil:\u00a0Un=2n\u22121<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span>n<\/span>\u2212<\/span><\/span>1<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                          • \n

                            U15=2\u00d715\u22121=30\u22121=29<\/span>U<\/span>15<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span>\u00d7<\/span><\/span>15<\/span>\u2212<\/span><\/span>1<\/span>=<\/span><\/span>30<\/span>\u2212<\/span><\/span>1<\/span>=<\/span><\/span>29<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                            Jawaban: 29<\/strong><\/p>\n

                            \n

                            Soal 12 (Pola Bilangan Genap)<\/h3>\n

                            Tentukan suku ke-12 dari barisan: 2, 4, 6, 8, …<\/p>\n

                            Pembahasan:<\/strong><\/p>\n

                              \n
                            • \n

                              Pola genap:\u00a0Un=2n<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span>n<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                            • \n

                              U12=2\u00d712=24<\/span>U<\/span>12<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span>\u00d7<\/span><\/span>12<\/span>=<\/span><\/span>24<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                              Jawaban: 24<\/strong><\/p>\n

                              \n

                              Soal 13 (Pola Bilangan Persegi Panjang)<\/h3>\n

                              Tentukan suku ke-8 dari barisan: 2, 6, 12, 20, …<\/p>\n

                              Pembahasan:<\/strong><\/p>\n

                                \n
                              • \n

                                Pola persegi panjang:\u00a0Un=n(n+1)<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>n<\/span>(<\/span>n<\/span>+<\/span><\/span>1<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                              • \n

                                U8=8\u00d79=72<\/span>U<\/span>8<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>8<\/span>\u00d7<\/span><\/span>9<\/span>=<\/span><\/span>72<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                                Jawaban: 72<\/strong><\/p>\n

                                \n

                                Soal 14 (Barisan Geometri dalam Soal Cerita Tabungan)<\/h3>\n

                                Seorang anak menabung setiap minggu dengan kelipatan tetap. Minggu pertama Rp5.000, minggu kedua Rp10.000, minggu ketiga Rp20.000. Berapa tabungan pada minggu ke-8?<\/p>\n

                                Pembahasan:<\/strong><\/p>\n

                                  \n
                                • \n

                                  a=5.000<\/span>a<\/span>=<\/span><\/span>5.000<\/span><\/span><\/span><\/span>,\u00a0r=10.000\u00f75.000=2<\/span>r<\/span>=<\/span><\/span>10.000<\/span>\u00f7<\/span><\/span>5.000<\/span>=<\/span><\/span>2<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                                • \n

                                  U8=5.000\u00d727=5.000\u00d7128=640.000<\/span>U<\/span>8<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>5.000<\/span>\u00d7<\/span><\/span>27<\/span><\/span><\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>5.000<\/span>\u00d7<\/span><\/span>128<\/span>=<\/span><\/span>640.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                                  Jawaban: Rp640.000<\/strong><\/p>\n

                                  \n

                                  Soal 15 (Pola Segitiga dari Susunan Segitiga)<\/h3>\n

                                  Perhatikan pola susunan segitiga berikut:<\/p>\n

                                    \n
                                  • \n

                                    Pola 1: 1 segitiga<\/p>\n<\/li>\n

                                  • \n

                                    Pola 2: 3 segitiga<\/p>\n<\/li>\n

                                  • \n

                                    Pola 3: 5 segitiga<\/p>\n<\/li>\n

                                  • \n

                                    Pola 4: 7 segitiga<\/p>\n<\/li>\n<\/ul>\n

                                    Berapa segitiga pada pola ke-15?<\/p>\n

                                    Pembahasan:<\/strong><\/p>\n

                                      \n
                                    • \n

                                      Barisan: 1, 3, 5, 7, … \u2192 barisan bilangan ganjil<\/p>\n<\/li>\n

                                    • \n

                                      Un=2n\u22121<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span>n<\/span>\u2212<\/span><\/span>1<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                                    • \n

                                      U15=2\u00d715\u22121=30\u22121=29<\/span>U<\/span>15<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span>\u00d7<\/span><\/span>15<\/span>\u2212<\/span><\/span>1<\/span>=<\/span><\/span>30<\/span>\u2212<\/span><\/span>1<\/span>=<\/span><\/span>29<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                                      Jawaban: 29 segitiga<\/strong><\/p>\n

                                      \n

                                      Ringkasan Rumus Penting Barisan Bilangan<\/h2>\n
                                      \n
                                      \n
                                      <\/div>\n
                                      <\/div>\n<\/div>\n\n\n\n\n\n\n\n\n\n\n\n
                                      Jenis Barisan<\/th>\nRumus Suku ke-n (Un<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>)<\/th>\nContoh<\/th>\n<\/tr>\n<\/thead>\n
                                      Aritmetika<\/strong><\/td>\nUn=a+(n\u22121)b<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>+<\/span><\/span>(<\/span>n<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>b<\/span><\/span><\/span><\/span><\/td>\n7, 12, 17, …<\/td>\n<\/tr>\n
                                      Geometri<\/strong><\/td>\nUn=a\u00d7rn\u22121<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>\u00d7<\/span><\/span>r<\/span>n<\/span>\u2212<\/span>1<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/td>\n3, 6, 12, …<\/td>\n<\/tr>\n
                                      Persegi<\/strong><\/td>\nUn=n2<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>n<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/td>\n1, 4, 9, 16, …<\/td>\n<\/tr>\n
                                      Segitiga<\/strong><\/td>\nUn=n(n+1)2<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span><\/span>n<\/span>(<\/span>n<\/span>+<\/span>1)<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/td>\n1, 3, 6, 10, …<\/td>\n<\/tr>\n
                                      Persegi panjang<\/strong><\/td>\nUn=n(n+1)<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>n<\/span>(<\/span>n<\/span>+<\/span><\/span>1<\/span>)<\/span><\/span><\/span><\/span><\/td>\n2, 6, 12, 20, …<\/td>\n<\/tr>\n
                                      Ganjil<\/strong><\/td>\nUn=2n\u22121<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span>n<\/span>\u2212<\/span><\/span>1<\/span><\/span><\/span><\/span><\/td>\n1, 3, 5, 7, …<\/td>\n<\/tr>\n
                                      Genap<\/strong><\/td>\nUn=2n<\/span>U<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span>n<\/span><\/span><\/span><\/span><\/td>\n2, 4, 6, 8, …<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

                                      Keterangan:<\/strong><\/p>\n

                                        \n
                                      • \n

                                        a<\/span>a<\/span><\/span><\/span><\/span>\u00a0= suku pertama<\/p>\n<\/li>\n

                                      • \n

                                        b<\/span>b<\/span><\/span><\/span><\/span>\u00a0= beda (untuk aritmetika)<\/p>\n<\/li>\n

                                      • \n

                                        r<\/span>r<\/span><\/span><\/span><\/span>\u00a0= rasio (untuk geometri)<\/p>\n<\/li>\n

                                      • \n

                                        n<\/span>n<\/span><\/span><\/span><\/span>\u00a0= nomor suku<\/p>\n<\/li>\n<\/ul>\n

                                        \n

                                        Sahabat Rumah Pintar<\/strong>, dengan menguasai 15 soal di atas, kalian sudah siap mengenali pola, menentukan jenis barisan, dan menghitung suku ke-n dari berbagai variasi soal barisan bilangan di TKA Matematika SMP. Ingat kuncinya:\u00a0amati selisih antar suku untuk aritmetika, rasio antar suku untuk geometri, dan kenali pola khusus seperti persegi, segitiga, ganjil, dan genap<\/strong>. Terus berlatih, ya!\u00a0Tetap pintar, tetap santai!<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"

                                        Bimbel Rumah Pintar – Soal barisan berhingga bilangan adalah urutan bilangan yang memiliki jumlah suku terbatas dengan pola atau aturan tertentu yang konsisten. Prinsip dasar yang harus dikuasai adalah kemampuan mengamati pola dari suku-suku yang diberikan. Kemudian mengidentifikasi jenis barisan […]<\/p>\n","protected":false},"author":1,"featured_media":2130,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"set","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[4],"tags":[236,235,224],"class_list":["post-2129","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-bahas-soal","tag-baris-bilangan","tag-pola-bilangan","tag-soal-tka-matematika-smp"],"_links":{"self":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2129","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/comments?post=2129"}],"version-history":[{"count":2,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2129\/revisions"}],"predecessor-version":[{"id":2132,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2129\/revisions\/2132"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/media\/2130"}],"wp:attachment":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/media?parent=2129"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/categories?post=2129"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/tags?post=2129"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}