{"id":2110,"date":"2026-04-03T12:17:25","date_gmt":"2026-04-03T12:17:25","guid":{"rendered":"https:\/\/rumahpintar.co.id\/blog\/?p=2110"},"modified":"2026-04-08T09:21:26","modified_gmt":"2026-04-08T09:21:26","slug":"15-contoh-soal-pertidaksamaan-linear-satu-variabel","status":"publish","type":"post","link":"https:\/\/rumahpintar.co.id\/blog\/15-contoh-soal-pertidaksamaan-linear-satu-variabel\/","title":{"rendered":"15 Contoh Soal Pertidaksamaan Linear Satu Variabel & Pembahasannya untuk TKA SMP"},"content":{"rendered":"

Bimbel Rumah Pintar<\/a> \u2013\u00a0<\/strong>Soal pertidaksamaan linear satu variabel (PtLSV) adalah kalimat matematika yang memuat satu variabel berpangkat satu dan menggunakan tanda ketidaksamaan seperti <<\/span><<\/span><\/span><\/span><\/span>,\u00a0><\/span>><\/span><\/span><\/span><\/span>,\u00a0\u2264<\/span>\u2264<\/span><\/span><\/span><\/span>, atau\u00a0\u2265<\/span>\u2265<\/span><\/span><\/span><\/span>. Prinsip dasarnya mirip dengan persamaan linear, namun ada satu aturan yang sangat krusial:\u00a0jika kedua ruas dikali atau dibagi dengan bilangan negatif, maka tanda pertidaksamaan harus dibalik<\/strong>\u00a0(misalnya\u00a0<<\/span><<\/span><\/span><\/span><\/span>\u00a0menjadi\u00a0><\/span>><\/span><\/span><\/span><\/span>).<\/p>\n

Selain itu, kemampuan menerjemahkan kata kunci seperti “tidak lebih dari” (\u2264<\/span>\u2264<\/span><\/span><\/span><\/span>), “paling sedikit” (\u2265<\/span>\u2265<\/span><\/span><\/span><\/span>), “lebih dari” (><\/span>><\/span><\/span><\/span><\/span>), dan “kurang dari” (<<\/span><<\/span><\/span><\/span><\/span>) menjadi model matematika menjadi kunci utama dalam menyelesaikan soal cerita.<\/p>\n

Mengapa latihan soal pertidaksamaan sangat penting?<\/strong>\u00a0Soal TKA Matematika SMP sering menyajikan PtLSV dalam bentuk masalah kontekstual seperti anggaran biaya pengantaran, batas maksimal parkir, syarat kelulusan nilai minimal, hingga masalah bisnis dan produksi.<\/p>\n

Tanpa latihan yang cukup, siswa sering lupa membalik tanda saat mengalikan\/membagi dengan bilangan negatif, salah menerjemahkan kata kunci, atau tidak menafsirkan hasil dengan tepat (misalnya jumlah orang harus bilangan bulat). Dengan menguasai 15 variasi soal berikut, Sahabat Rumah Pintar akan mampu membuat model pertidaksamaan dengan tepat, menyelesaikannya dengan benar, dan menjawab soal TKA dengan percaya diri.<\/p>\n

15 Contoh Soal Pertidaksamaan Linear Satu Variabel<\/h2>\n

<\/h3>\n

Soal 1 (Model Pertidaksamaan dari Soal Cerita)<\/h3>\n

Sebuah jasa pengantaran barang mengenakan biaya tetap pemesanan Rp12.000,00 dan biaya pengantaran Rp4.000,00 per kilometer. Seorang pelanggan memiliki anggaran tidak lebih dari Rp40.000,00 untuk satu kali pemesanan. Jika\u00a0x<\/span>x<\/span><\/span><\/span><\/span>\u00a0menyatakan jarak pengantaran (dalam km), maka permasalahan dapat dimodelkan dengan ….<\/p>\n

Pembahasan:<\/strong><\/p>\n

    \n
  • \n

    Biaya total = biaya tetap + (biaya per km \u00d7 jarak)<\/p>\n<\/li>\n

  • \n

    Biaya total =\u00a012.000+4.000x<\/span>12.000<\/span>+<\/span><\/span>4.000<\/span>x<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

  • \n

    Anggaran “tidak lebih dari” Rp40.000 \u2192\u00a0\u226440.000<\/span>\u2264<\/span><\/span>40.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

  • \n

    Model:\u00a04.000x+12.000\u226440.000<\/span>4.000<\/span>x<\/span>+<\/span><\/span>12.000<\/span>\u2264<\/span><\/span>40.000<\/span><\/span><\/span><\/span><\/strong><\/p>\n<\/li>\n<\/ul>\n

    Jawaban:\u00a04.000x+12.000\u226440.000<\/span>4.000<\/span>x<\/span>+<\/span><\/span>12.000<\/span>\u2264<\/span><\/span>40.000<\/span><\/span><\/span><\/span><\/strong><\/p>\n

    \n

    Soal 2 (Menyelesaikan Model Pertidaksamaan)<\/h3>\n

    Dari model\u00a04.000x+12.000\u226440.000<\/span>4.000<\/span>x<\/span>+<\/span><\/span>12.000<\/span>\u2264<\/span><\/span>40.000<\/span><\/span><\/span><\/span>, berapa jarak maksimal yang dapat dijangkau pelanggan?<\/p>\n

    Pembahasan:<\/strong><\/p>\n

      \n
    • \n

      4.000x+12.000\u226440.000<\/span>4.000<\/span>x<\/span>+<\/span><\/span>12.000<\/span>\u2264<\/span><\/span>40.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

    • \n

      4.000x\u226440.000\u221212.000<\/span>4.000<\/span>x<\/span>\u2264<\/span><\/span>40.000<\/span>\u2212<\/span><\/span>12.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

    • \n

      4.000x\u226428.000<\/span>4.000<\/span>x<\/span>\u2264<\/span><\/span>28.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

    • \n

      x\u226428.000\u00f74.000<\/span>x<\/span>\u2264<\/span><\/span>28.000<\/span>\u00f7<\/span><\/span>4.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

    • \n

      x\u22647<\/span>x<\/span>\u2264<\/span><\/span>7<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

      Jawaban: Jarak maksimal 7 km<\/strong><\/p>\n

      \n

      Soal 3 (Pertidaksamaan dengan Tanda Negatif \u2013 Pembalikan Tanda)<\/h3>\n

      Selesaikan\u00a0\u22123x+6>15<\/span>\u2212<\/span>3<\/span>x<\/span>+<\/span><\/span>6<\/span>><\/span><\/span>15<\/span><\/span><\/span><\/span><\/p>\n

      Pembahasan:<\/strong><\/p>\n

        \n
      • \n

        \u22123x+6>15<\/span>\u2212<\/span>3<\/span>x<\/span>+<\/span><\/span>6<\/span>><\/span><\/span>15<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

      • \n

        \u22123x>15\u22126<\/span>\u2212<\/span>3<\/span>x<\/span>><\/span><\/span>15<\/span>\u2212<\/span><\/span>6<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

      • \n

        \u22123x>9<\/span>\u2212<\/span>3<\/span>x<\/span>><\/span><\/span>9<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

      • \n

        Bagi kedua ruas dengan -3 \u2192\u00a0tanda dibalik<\/strong>\u00a0(><\/span>><\/span><\/span><\/span><\/span>\u00a0menjadi\u00a0<<\/span><<\/span><\/span><\/span><\/span>)<\/p>\n<\/li>\n

      • \n

        x<9\u00f7(\u22123)<\/span>x<\/span><<\/span><\/span>9<\/span>\u00f7<\/span><\/span>(<\/span>\u2212<\/span>3<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

      • \n

        x<\u22123<\/span>x<\/span><<\/span><\/span>\u2212<\/span>3<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

        Jawaban:\u00a0x<\u22123<\/span>x<\/span><<\/span><\/span>\u2212<\/span>3<\/span><\/span><\/span><\/span><\/strong><\/p>\n

        \n

        Soal 4 (Variabel di Kedua Ruas)<\/h3>\n

        Selesaikan\u00a02x+5\u22643x\u22122<\/span>2<\/span>x<\/span>+<\/span><\/span>5<\/span>\u2264<\/span><\/span>3<\/span>x<\/span>\u2212<\/span><\/span>2<\/span><\/span><\/span><\/span><\/p>\n

        Pembahasan:<\/strong><\/p>\n

          \n
        • \n

          2x+5\u22643x\u22122<\/span>2<\/span>x<\/span>+<\/span><\/span>5<\/span>\u2264<\/span><\/span>3<\/span>x<\/span>\u2212<\/span><\/span>2<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

        • \n

          2x\u22123x\u2264\u22122\u22125<\/span>2<\/span>x<\/span>\u2212<\/span><\/span>3<\/span>x<\/span>\u2264<\/span><\/span>\u2212<\/span>2<\/span>\u2212<\/span><\/span>5<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

        • \n

          \u2212x\u2264\u22127<\/span>\u2212<\/span>x<\/span>\u2264<\/span><\/span>\u2212<\/span>7<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

        • \n

          Kalikan kedua ruas dengan -1 \u2192 tanda dibalik (\u2264<\/span>\u2264<\/span><\/span><\/span><\/span>\u00a0menjadi\u00a0\u2265<\/span>\u2265<\/span><\/span><\/span><\/span>)<\/p>\n<\/li>\n

        • \n

          x\u22657<\/span>x<\/span>\u2265<\/span><\/span>7<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

          Jawaban:\u00a0x\u22657<\/span>x<\/span>\u2265<\/span><\/span>7<\/span><\/span><\/span><\/span><\/strong><\/p>\n

          \n

          Soal 5 (Soal Cerita \u2013 Batas Maksimal Tarif Taksi)<\/h3>\n

          Sebuah taksi mengenakan biaya buka pintu Rp8.000 dan tarif per km Rp3.500. Jika seseorang membawa uang Rp50.000, berapa km maksimal yang dapat ditempuh?<\/p>\n

          Pembahasan:<\/strong><\/p>\n

            \n
          • \n

            Model:\u00a08.000+3.500x\u226450.000<\/span>8.000<\/span>+<\/span><\/span>3.500<\/span>x<\/span>\u2264<\/span><\/span>50.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

          • \n

            3.500x\u226442.000<\/span>3.500<\/span>x<\/span>\u2264<\/span><\/span>42.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

          • \n

            x\u226442.000\u00f73.500<\/span>x<\/span>\u2264<\/span><\/span>42.000<\/span>\u00f7<\/span><\/span>3.500<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

          • \n

            x\u226412<\/span>x<\/span>\u2264<\/span><\/span>12<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

            Jawaban: Maksimal 12 km<\/strong><\/p>\n

            \n

            Soal 6 (Soal Cerita \u2013 Batas Minimal Nilai)<\/h3>\n

            Untuk mengikuti suatu lomba, nilai minimal peserta adalah 75. Nilai Andi adalah\u00a05x+10<\/span>5<\/span>x<\/span>+<\/span><\/span>10<\/span><\/span><\/span><\/span>\u00a0dengan\u00a0x<\/span>x<\/span><\/span><\/span><\/span>\u00a0adalah jumlah soal yang benar. Berapa jumlah soal benar minimal yang harus dicapai Andi?<\/p>\n

            Pembahasan:<\/strong><\/p>\n

              \n
            • \n

              Model:\u00a05x+10\u226575<\/span>5<\/span>x<\/span>+<\/span><\/span>10<\/span>\u2265<\/span><\/span>75<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

            • \n

              5x\u226565<\/span>5<\/span>x<\/span>\u2265<\/span><\/span>65<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

            • \n

              x\u226513<\/span>x<\/span>\u2265<\/span><\/span>13<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

              Jawaban: Minimal 13 soal benar<\/strong><\/p>\n

              \n

              Soal 7 (Pertidaksamaan dengan Pecahan)<\/h3>\n

              Selesaikan\u00a0x2+3>5<\/span>2<\/span><\/span>x<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>3<\/span>><\/span><\/span>5<\/span><\/span><\/span><\/span><\/p>\n

              Pembahasan:<\/strong><\/p>\n

                \n
              • \n

                x2+3>5<\/span>2<\/span><\/span>x<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>3<\/span>><\/span><\/span>5<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

              • \n

                x2>5\u22123<\/span>2<\/span><\/span>x<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>><\/span><\/span>5<\/span>\u2212<\/span><\/span>3<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

              • \n

                x2>2<\/span>2<\/span><\/span>x<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>><\/span><\/span>2<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

              • \n

                Kalikan kedua ruas dengan 2 (positif) \u2192 tanda tetap<\/p>\n<\/li>\n

              • \n

                x>4<\/span>x<\/span>><\/span><\/span>4<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                Jawaban:\u00a0x>4<\/span>x<\/span>><\/span><\/span>4<\/span><\/span><\/span><\/span><\/strong><\/p>\n

                \n

                Soal 8 (Pertidaksamaan dengan Bilangan Negatif di Pembagi)<\/h3>\n

                Selesaikan\u00a0x\u22122\u22644<\/span>\u22122<\/span><\/span>x<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u2264<\/span><\/span>4<\/span><\/span><\/span><\/span><\/p>\n

                Pembahasan:<\/strong><\/p>\n

                  \n
                • \n

                  x\u22122\u22644<\/span>\u22122<\/span><\/span>x<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u2264<\/span><\/span>4<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                • \n

                  Kalikan kedua ruas dengan -2 (negatif) \u2192\u00a0tanda dibalik<\/strong>\u00a0(\u2264<\/span>\u2264<\/span><\/span><\/span><\/span>\u00a0menjadi\u00a0\u2265<\/span>\u2265<\/span><\/span><\/span><\/span>)<\/p>\n<\/li>\n

                • \n

                  x\u22654\u00d7(\u22122)<\/span>x<\/span>\u2265<\/span><\/span>4<\/span>\u00d7<\/span><\/span>(<\/span>\u2212<\/span>2<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                • \n

                  x\u2265\u22128<\/span>x<\/span>\u2265<\/span><\/span>\u2212<\/span>8<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                  Jawaban:\u00a0x\u2265\u22128<\/span>x<\/span>\u2265<\/span><\/span>\u2212<\/span>8<\/span><\/span><\/span><\/span><\/strong><\/p>\n

                  \n

                  Soal 9 (Soal Cerita \u2013 Parkir Maksimal)<\/h3>\n

                  Sebuah warung memasang tarif parkir Rp2.000 untuk 1 jam pertama dan Rp1.500 per jam berikutnya. Jika seseorang membawa uang Rp15.000, berapa jam maksimal ia dapat parkir?<\/p>\n

                  Pembahasan:<\/strong><\/p>\n

                    \n
                  • \n

                    Biaya 1 jam pertama = Rp2.000<\/p>\n<\/li>\n

                  • \n

                    Sisa uang untuk jam berikutnya =\u00a015.000\u22122.000=13.000<\/span>15.000<\/span>\u2212<\/span><\/span>2.000<\/span>=<\/span><\/span>13.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                  • \n

                    Jam berikutnya maksimal =\u00a013.000\u00f71.500=8,66…<\/span>13.000<\/span>\u00f7<\/span><\/span>1.500<\/span>=<\/span><\/span>8<\/span>,<\/span>66…<\/span><\/span><\/span><\/span>\u00a0\u2192 8 jam<\/p>\n<\/li>\n

                  • \n

                    Total jam maksimal =\u00a01+8=9<\/span>1<\/span>+<\/span><\/span>8<\/span>=<\/span><\/span>9<\/span><\/span><\/span><\/span>\u00a0jam<\/p>\n<\/li>\n

                  • \n

                    Atau dengan model:\u00a02.000+1.500(x\u22121)\u226415.000<\/span>2.000<\/span>+<\/span><\/span>1.500<\/span>(<\/span>x<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>\u2264<\/span><\/span>15.000<\/span><\/span><\/span><\/span>\u00a0untuk\u00a0x\u22651<\/span>x<\/span>\u2265<\/span><\/span>1<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                  • \n

                    1.500(x\u22121)\u226413.000<\/span>1.500<\/span>(<\/span>x<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>\u2264<\/span><\/span>13.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                  • \n

                    x\u22121\u22648,67<\/span>x<\/span>\u2212<\/span><\/span>1<\/span>\u2264<\/span><\/span>8<\/span>,<\/span>67<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                  • \n

                    x\u22649,67<\/span>x<\/span>\u2264<\/span><\/span>9<\/span>,<\/span>67<\/span><\/span><\/span><\/span>\u00a0\u2192 maksimal\u00a0x=9<\/span>x<\/span>=<\/span><\/span>9<\/span><\/span><\/span><\/span>\u00a0jam<\/p>\n<\/li>\n<\/ul>\n

                    Jawaban: 9 jam<\/strong><\/p>\n

                    \n

                    Soal 10 (Soal Cerita \u2013 Syarat Kelulusan)<\/h3>\n

                    Nilai ujian matematika dinyatakan dengan\u00a08n\u221220<\/span>8<\/span>n<\/span>\u2212<\/span><\/span>20<\/span><\/span><\/span><\/span>, dengan\u00a0n<\/span>n<\/span><\/span><\/span><\/span>\u00a0adalah jumlah soal benar. Jika syarat lulus adalah nilai minimal 60, berapa jumlah soal benar minimal?<\/p>\n

                    Pembahasan:<\/strong><\/p>\n

                      \n
                    • \n

                      Model:\u00a08n\u221220\u226560<\/span>8<\/span>n<\/span>\u2212<\/span><\/span>20<\/span>\u2265<\/span><\/span>60<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                    • \n

                      8n\u226580<\/span>8<\/span>n<\/span>\u2265<\/span><\/span>80<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                    • \n

                      n\u226510<\/span>n<\/span>\u2265<\/span><\/span>10<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                      Jawaban: Minimal 10 soal benar<\/strong><\/p>\n

                      \n

                      Soal 11 (Pertidaksamaan dengan Distributif)<\/h3>\n

                      Selesaikan\u00a03(x\u22124)\u22652(x+1)<\/span>3<\/span>(<\/span>x<\/span>\u2212<\/span><\/span>4<\/span>)<\/span>\u2265<\/span><\/span>2<\/span>(<\/span>x<\/span>+<\/span><\/span>1<\/span>)<\/span><\/span><\/span><\/span><\/p>\n

                      Pembahasan:<\/strong><\/p>\n

                        \n
                      • \n

                        3x\u221212\u22652x+2<\/span>3<\/span>x<\/span>\u2212<\/span><\/span>12<\/span>\u2265<\/span><\/span>2<\/span>x<\/span>+<\/span><\/span>2<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                      • \n

                        3x\u22122x\u22652+12<\/span>3<\/span>x<\/span>\u2212<\/span><\/span>2<\/span>x<\/span>\u2265<\/span><\/span>2<\/span>+<\/span><\/span>12<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                      • \n

                        x\u226514<\/span>x<\/span>\u2265<\/span><\/span>14<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                        Jawaban:\u00a0x\u226514<\/span>x<\/span>\u2265<\/span><\/span>14<\/span><\/span><\/span><\/span><\/strong><\/p>\n

                        \n

                        Soal 12 (Soal Tipe PGK \u2013 Pernyataan Benar Lebih dari Satu)<\/h3>\n

                        Berdasarkan permasalahan jasa pengantaran pada Soal 1, manakah pernyataan yang BENAR?<\/p>\n

                        A. Model pertidaksamaannya adalah\u00a04.000x+12.000\u226440.000<\/span>4.000<\/span>x<\/span>+<\/span><\/span>12.000<\/span>\u2264<\/span><\/span>40.000<\/span><\/span><\/span><\/span>
                        \nB. Jarak maksimal yang dapat dijangkau adalah 7 km
                        \nC. Jika jarak 8 km, biaya melebihi anggaran
                        \nD. Jika jarak 5 km, biaya yang dikeluarkan adalah Rp30.000<\/p>\n

                        Pembahasan:<\/strong><\/p>\n

                          \n
                        • \n

                          A: Benar (dari Soal 1)<\/p>\n<\/li>\n

                        • \n

                          B: Benar (dari Soal 2)<\/p>\n<\/li>\n

                        • \n

                          C: Biaya 8 km =\u00a04.000\u00d78+12.000=32.000+12.000=44.000>40.000<\/span>4.000<\/span>\u00d7<\/span><\/span>8<\/span>+<\/span><\/span>12.000<\/span>=<\/span><\/span>32.000<\/span>+<\/span><\/span>12.000<\/span>=<\/span><\/span>44.000<\/span>><\/span><\/span>40.000<\/span><\/span><\/span><\/span>\u00a0\u2192 Benar<\/p>\n<\/li>\n

                        • \n

                          D: Biaya 5 km =\u00a04.000\u00d75+12.000=20.000+12.000=32.000<\/span>4.000<\/span>\u00d7<\/span><\/span>5<\/span>+<\/span><\/span>12.000<\/span>=<\/span><\/span>20.000<\/span>+<\/span><\/span>12.000<\/span>=<\/span><\/span>32.000<\/span><\/span><\/span><\/span>\u00a0\u2192 Rp32.000, bukan Rp30.000 \u2192 Salah<\/p>\n<\/li>\n<\/ul>\n

                          Jawaban: A, B, C<\/strong><\/p>\n

                          \n

                          Soal 13 (Soal Cerita \u2013 Rekrutmen Karyawan)<\/h3>\n

                          Sebuah perusahaan membutuhkan minimal 100 karyawan. Saat ini ada 60 karyawan tetap. Perusahaan akan merekrut karyawan kontrak sebanyak\u00a02x+5<\/span>2<\/span>x<\/span>+<\/span><\/span>5<\/span><\/span><\/span><\/span>\u00a0orang. Berapa nilai\u00a0x<\/span>x<\/span><\/span><\/span><\/span>\u00a0minimal?<\/p>\n

                          Pembahasan:<\/strong><\/p>\n

                            \n
                          • \n

                            Model:\u00a060+(2x+5)\u2265100<\/span>60<\/span>+<\/span><\/span>(<\/span>2<\/span>x<\/span>+<\/span><\/span>5<\/span>)<\/span>\u2265<\/span><\/span>100<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                          • \n

                            2x+65\u2265100<\/span>2<\/span>x<\/span>+<\/span><\/span>65<\/span>\u2265<\/span><\/span>100<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                          • \n

                            2x\u226535<\/span>2<\/span>x<\/span>\u2265<\/span><\/span>35<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                          • \n

                            x\u226517,5<\/span>x<\/span>\u2265<\/span><\/span>17<\/span>,<\/span>5<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                          • \n

                            Karena\u00a0x<\/span>x<\/span><\/span><\/span><\/span>\u00a0biasanya bilangan bulat, maka\u00a0x\u226518<\/span>x<\/span>\u2265<\/span><\/span>18<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                            Jawaban:\u00a0x<\/span>x<\/span><\/span><\/span><\/span>\u00a0minimal 18<\/strong><\/p>\n

                            \n

                            Soal 14 (Pertidaksamaan dengan Dua Operasi)<\/h3>\n

                            Selesaikan\u00a02(3x\u22125)+4\u22643(2x+1)\u22127<\/span>2<\/span>(<\/span>3<\/span>x<\/span>\u2212<\/span><\/span>5<\/span>)<\/span>+<\/span><\/span>4<\/span>\u2264<\/span><\/span>3<\/span>(<\/span>2<\/span>x<\/span>+<\/span><\/span>1<\/span>)<\/span>\u2212<\/span><\/span>7<\/span><\/span><\/span><\/span><\/p>\n

                            Pembahasan:<\/strong><\/p>\n

                              \n
                            • \n

                              6x\u221210+4\u22646x+3\u22127<\/span>6<\/span>x<\/span>\u2212<\/span><\/span>10<\/span>+<\/span><\/span>4<\/span>\u2264<\/span><\/span>6<\/span>x<\/span>+<\/span><\/span>3<\/span>\u2212<\/span><\/span>7<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                            • \n

                              6x\u22126\u22646x\u22124<\/span>6<\/span>x<\/span>\u2212<\/span><\/span>6<\/span>\u2264<\/span><\/span>6<\/span>x<\/span>\u2212<\/span><\/span>4<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                            • \n

                              6x\u22126x\u2264\u22124+6<\/span>6<\/span>x<\/span>\u2212<\/span><\/span>6<\/span>x<\/span>\u2264<\/span><\/span>\u2212<\/span>4<\/span>+<\/span><\/span>6<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                            • \n

                              0\u22642<\/span>0<\/span>\u2264<\/span><\/span>2<\/span><\/span><\/span><\/span>\u00a0(pernyataan yang selalu benar)<\/p>\n<\/li>\n<\/ul>\n

                              Jawaban: Semua bilangan real\u00a0x<\/span>x<\/span><\/span><\/span><\/span>\u00a0memenuhi (HP =\u00a0R<\/span>R<\/span><\/span><\/span><\/span>)<\/strong><\/p>\n

                              \n

                              Soal 15 (Soal Cerita \u2013 Diskon dan Anggaran)<\/h3>\n

                              Sebuah toko memberikan diskon 20%. Jika harga setelah diskon tidak boleh lebih dari Rp120.000, berapa harga maksimal sebelum diskon?<\/p>\n

                              Pembahasan:<\/strong><\/p>\n

                                \n
                              • \n

                                Harga setelah diskon = harga awal \u00d7 (100% – 20%) =\u00a00,8\u00d7harga\u00a0awal<\/span>0<\/span>,<\/span>8<\/span>\u00d7<\/span><\/span>harga\u00a0awal<\/span><\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                              • \n

                                Model:\u00a00,8x\u2264120.000<\/span>0<\/span>,<\/span>8<\/span>x<\/span>\u2264<\/span><\/span>120.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                              • \n

                                x\u2264120.000\u00f70,8<\/span>x<\/span>\u2264<\/span><\/span>120.000<\/span>\u00f7<\/span><\/span>0<\/span>,<\/span>8<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                              • \n

                                x\u2264150.000<\/span>x<\/span>\u2264<\/span><\/span>150.000<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                                Jawaban: Harga maksimal sebelum diskon = Rp150.000<\/strong><\/p>\n

                                Ringkasan SEO untuk Artikel<\/span><\/p>\n

                                \n
                                \n
                                <\/div>\n
                                <\/div>\n<\/div>\n\n\n\n\n\n\n\n\n\n
                                Elemen<\/th>\nIsi<\/th>\n<\/tr>\n<\/thead>\n
                                Keyword utama<\/strong><\/td>\nPertidaksamaan Linear Satu Variabel<\/td>\n<\/tr>\n
                                Keyword sekunder<\/strong><\/td>\nPtLSV, soal TKA Matematika SMP, contoh soal pertidaksamaan, pembalikan tanda, model matematika<\/td>\n<\/tr>\n
                                Judul<\/strong><\/td>\nPertidaksamaan Linear Satu Variabel: 15 Soal & Pembahasan TKA SMP<\/td>\n<\/tr>\n
                                Meta deskripsi<\/strong><\/td>\nLatihan 15 soal pertidaksamaan linear satu variabel (PtLSV). Model cerita, pembalikan tanda, batas maksimal. Siap TKA SMP! (120 karakter)<\/td>\n<\/tr>\n
                                Target pembaca<\/strong><\/td>\nSiswa SMP kelas 7,8,9 yang mempersiapkan ujian TKA Matematika<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

                                Ringkasan Aturan Penting Pertidaksamaan Linear Satu Variabel<\/h2>\n
                                \n
                                \n
                                <\/div>\n
                                <\/div>\n<\/div>\n\n\n\n\n\n\n\n\n\n
                                Aturan<\/th>\nKeterangan<\/th>\nContoh<\/th>\n<\/tr>\n<\/thead>\n
                                Tambah\/kurang kedua ruas<\/td>\nTanda tetap<\/td>\nx\u22123<5\u2192x<8<\/span>x<\/span>\u2212<\/span><\/span>3<\/span><<\/span><\/span>5<\/span>\u2192<\/span><\/span>x<\/span><<\/span><\/span>8<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n
                                Kali\/bagi dengan bilangan positif<\/td>\nTanda tetap<\/td>\n2x<10\u2192x<5<\/span>2<\/span>x<\/span><<\/span><\/span>10<\/span>\u2192<\/span><\/span>x<\/span><<\/span><\/span>5<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n
                                Kali\/bagi dengan bilangan negatif<\/td>\nTanda dibalik<\/strong><\/td>\n\u22123x<12\u2192x>\u22124<\/span>\u2212<\/span>3<\/span>x<\/span><<\/span><\/span>12<\/span>\u2192<\/span><\/span>x<\/span>><\/span><\/span>\u2212<\/span>4<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n
                                a<b<\/span>a<\/span><<\/span><\/span>b<\/span><\/span><\/span><\/span><\/td>\nBulatan kosong pada garis bilangan<\/td>\nx>2<\/span>x<\/span>><\/span><\/span>2<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n
                                a\u2264b<\/span>a<\/span>\u2264<\/span><\/span>b<\/span><\/span><\/span><\/span><\/td>\nBulatan penuh pada garis bilangan<\/td>\nx\u22652<\/span>x<\/span>\u2265<\/span><\/span>2<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

                                Terjemahan Kata Kunci ke Tanda:<\/strong><\/p>\n

                                \n
                                \n
                                <\/div>\n<\/div>\n\n\n\n\n\n\n\n\n
                                Kata\/Frasa<\/th>\nTanda<\/th>\nContoh Model<\/th>\n<\/tr>\n<\/thead>\n
                                Tidak lebih dari, paling banyak, maksimal<\/td>\n\u2264<\/span>\u2264<\/span><\/span><\/span><\/span><\/td>\nx\u226410<\/span>x<\/span>\u2264<\/span><\/span>10<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n
                                Tidak kurang dari, paling sedikit, minimal<\/td>\n\u2265<\/span>\u2265<\/span><\/span><\/span><\/span><\/td>\nx\u22655<\/span>x<\/span>\u2265<\/span><\/span>5<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n
                                Lebih dari<\/td>\n><\/span>><\/span><\/span><\/span><\/span><\/td>\nx>5<\/span>x<\/span>><\/span><\/span>5<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n
                                Kurang dari<\/td>\n<<\/span><<\/span><\/span><\/span><\/span><\/td>\nx<5<\/span>x<\/span><<\/span><\/span>5<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n
                                \n

                                Sahabat Rumah Pintar<\/strong>, dengan menguasai 15 soal di atas, kalian sudah siap membuat model, menyelesaikan, dan menafsirkan berbagai variasi soal pertidaksamaan linear satu variabel di TKA Matematika SMP.<\/p>\n

                                Ingat kuncinya:\u00a0perhatikan kata kunci soal, hati-hati dengan pembalikan tanda saat kali\/bagi negatif, dan tafsirkan hasil sesuai konteks (bilangan bulat, tidak negatif, dll)<\/strong>. Terus berlatih, ya!\u00a0Tetap pintar, tetap santai!<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"

                                Bimbel Rumah Pintar \u2013\u00a0Soal pertidaksamaan linear satu variabel (PtLSV) adalah kalimat matematika yang memuat satu variabel berpangkat satu dan menggunakan tanda ketidaksamaan seperti <<,\u00a0>>,\u00a0\u2264\u2264, atau\u00a0\u2265\u2265. Prinsip dasarnya mirip dengan persamaan linear, namun ada satu aturan yang sangat krusial:\u00a0jika kedua ruas […]<\/p>\n","protected":false},"author":1,"featured_media":2111,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"set","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[4],"tags":[227,228,225,226,229,207],"class_list":["post-2110","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-bahas-soal","tag-contoh-soal-pertidaksamaan","tag-pembalikan-tanda","tag-pertidaksamaan-linear-satu-variabel","tag-ptlsv","tag-soal-cerita-pertidaksamaan","tag-tka-matematika-smp"],"_links":{"self":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2110","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/comments?post=2110"}],"version-history":[{"count":1,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2110\/revisions"}],"predecessor-version":[{"id":2113,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2110\/revisions\/2113"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/media\/2111"}],"wp:attachment":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/media?parent=2110"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/categories?post=2110"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/tags?post=2110"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}