{"id":2104,"date":"2026-04-03T10:04:59","date_gmt":"2026-04-03T10:04:59","guid":{"rendered":"https:\/\/rumahpintar.co.id\/blog\/?p=2104"},"modified":"2026-04-08T09:10:07","modified_gmt":"2026-04-08T09:10:07","slug":"15-soal-bentuk-aljabar-dan-sifat-operasinya","status":"publish","type":"post","link":"https:\/\/rumahpintar.co.id\/blog\/15-soal-bentuk-aljabar-dan-sifat-operasinya\/","title":{"rendered":"15 Soal Bentuk Aljabar dan Sifat Operasinya, Lengkap dengan Pembahasan"},"content":{"rendered":"

Bimbel Rumah Pintar<\/a>\u00a0\u2013\u00a0Sahabat Rumah Pintar<\/strong>, memecahkan soal bentuk aljabar dan sifat operasinya tentu wajib bisa Kamu lakukan untuk sukses di TKA Matematika SMP. Perlu diketahui, bentuk aljabar adalah kalimat matematika yang memuat variabel (huruf pengganti bilangan yang belum diketahui), koefisien (bilangan yang mengalikan variabel), dan konstanta (bilangan tanpa variabel).<\/p>\n

Kunci utama menguasai aljabar terletak pada pemahaman tiga sifat operasi: komutatif<\/strong>\u00a0(pertukaran:\u00a0a+b=b+a<\/span>a<\/span>+<\/span><\/span>b<\/span>=<\/span><\/span>b<\/span>+<\/span><\/span>a<\/span><\/span><\/span><\/span>\u00a0dan\u00a0a\u00d7b=b\u00d7a<\/span>a<\/span>\u00d7<\/span><\/span>b<\/span>=<\/span><\/span>b<\/span>\u00d7<\/span><\/span>a<\/span><\/span><\/span><\/span>),\u00a0asosiatif<\/strong>\u00a0(pengelompokan:\u00a0(a+b)+c=a+(b+c)<\/span>(<\/span>a<\/span>+<\/span><\/span>b<\/span>)<\/span>+<\/span><\/span>c<\/span>=<\/span><\/span>a<\/span>+<\/span><\/span>(<\/span>b<\/span>+<\/span><\/span>c<\/span>)<\/span><\/span><\/span><\/span>\u00a0dan\u00a0(a\u00d7b)\u00d7c=a\u00d7(b\u00d7c)<\/span>(<\/span>a<\/span>\u00d7<\/span><\/span>b<\/span>)<\/span>\u00d7<\/span><\/span>c<\/span>=<\/span><\/span>a<\/span>\u00d7<\/span><\/span>(<\/span>b<\/span>\u00d7<\/span><\/span>c<\/span>)<\/span><\/span><\/span><\/span>), serta\u00a0distributif<\/strong>\u00a0(penyebaran:\u00a0a(b+c)=ab+ac<\/span>a<\/span>(<\/span>b<\/span>+<\/span><\/span>c<\/span>)<\/span>=<\/span><\/span>ab<\/span>+<\/span><\/span>a<\/span>c<\/span><\/span><\/span><\/span>).<\/p>\n

Selain itu, kemampuan mengidentifikasi\u00a0suku sejenis<\/strong>\u00a0(suku dengan variabel dan pangkat yang sama) menjadi fondasi dalam penjumlahan, pengurangan, perkalian, pemfaktoran, dan penyederhanaan bentuk aljabar.<\/p>\n

Mengapa latihan soal bentuk aljabar sangat penting?<\/strong>\u00a0Soal TKA Matematika SMP hampir selalu menghadirkan aljabar dalam berbagai bentuk, mulai dari penyederhanaan ekspresi, perkalian suku dua, pemfaktoran, hingga soal kontekstual yang membutuhkan manipulasi aljabar. Tanpa latihan yang cukup, siswa sering terjebak pada kesalahan tanda saat distributif dengan negatif, menjumlahkan suku tidak sejenis, atau lupa mengalikan semua suku dalam perkalian. Dengan menguasai 15 variasi soal berikut, Sahabat Rumah Pintar akan mampu menyederhanakan bentuk aljabar dengan cepat, memfaktorkan dengan tepat, dan menjawab soal TKA dengan percaya diri.<\/p>\n

\n

15 Contoh Soal dan Pembahasan Bentuk Aljabar<\/h2>\n
\n

Soal 1 (Penjumlahan & Pengurangan Suku Sejenis)<\/h3>\n

Sederhanakan\u00a05a+3b\u22122a+7b\u2212a<\/span>5<\/span>a<\/span>+<\/span><\/span>3<\/span>b<\/span>\u2212<\/span><\/span>2<\/span>a<\/span>+<\/span><\/span>7<\/span>b<\/span>\u2212<\/span><\/span>a<\/span><\/span><\/span><\/span><\/p>\n

Pembahasan:<\/strong><\/p>\n

    \n
  • \n

    Kelompokkan suku sejenis:\u00a0(5a\u22122a\u2212a)+(3b+7b)<\/span>(<\/span>5<\/span>a<\/span>\u2212<\/span><\/span>2<\/span>a<\/span>\u2212<\/span><\/span>a<\/span>)<\/span>+<\/span><\/span>(<\/span>3<\/span>b<\/span>+<\/span><\/span>7<\/span>b<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

  • \n

    (5\u22122\u22121)a=2a<\/span>(<\/span>5<\/span>\u2212<\/span><\/span>2<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>a<\/span>=<\/span><\/span>2<\/span>a<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

  • \n

    (3+7)b=10b<\/span>(<\/span>3<\/span>+<\/span><\/span>7<\/span>)<\/span>b<\/span>=<\/span><\/span>10<\/span>b<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

  • \n

    Hasil =\u00a02a+10b<\/span>2<\/span>a<\/span>+<\/span><\/span>10<\/span>b<\/span><\/span><\/span><\/span><\/strong><\/p>\n<\/li>\n<\/ul>\n

    Jawaban:\u00a02a+10b<\/span>2<\/span>a<\/span>+<\/span><\/span>10<\/span>b<\/span><\/span><\/span><\/span><\/strong><\/p>\n

    \n

    Soal 2 (Distributif dengan Tanda Kurung)<\/h3>\n

    Sederhanakan\u00a03(2x+4)\u22122(x\u22123)<\/span>3<\/span>(<\/span>2<\/span>x<\/span>+<\/span><\/span>4<\/span>)<\/span>\u2212<\/span><\/span>2<\/span>(<\/span>x<\/span>\u2212<\/span><\/span>3<\/span>)<\/span><\/span><\/span><\/span><\/p>\n

    Pembahasan:<\/strong><\/p>\n

      \n
    • \n

      3(2x+4)=6x+12<\/span>3<\/span>(<\/span>2<\/span>x<\/span>+<\/span><\/span>4<\/span>)<\/span>=<\/span><\/span>6<\/span>x<\/span>+<\/span><\/span>12<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

    • \n

      \u22122(x\u22123)=\u22122x+6<\/span>\u2212<\/span>2<\/span>(<\/span>x<\/span>\u2212<\/span><\/span>3<\/span>)<\/span>=<\/span><\/span>\u2212<\/span>2<\/span>x<\/span>+<\/span><\/span>6<\/span><\/span><\/span><\/span>\u00a0(perhatikan tanda minus!)<\/p>\n<\/li>\n

    • \n

      Jumlahkan:\u00a0(6x\u22122x)+(12+6)=4x+18<\/span>(<\/span>6<\/span>x<\/span>\u2212<\/span><\/span>2<\/span>x<\/span>)<\/span>+<\/span><\/span>(<\/span>12<\/span>+<\/span><\/span>6<\/span>)<\/span>=<\/span><\/span>4<\/span>x<\/span>+<\/span><\/span>18<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

      Jawaban:\u00a04x+18<\/span>4<\/span>x<\/span>+<\/span><\/span>18<\/span><\/span><\/span><\/span><\/strong><\/p>\n

      \n

      Soal 3 (Perkalian Suku Dua dengan Suku Dua)<\/h3>\n

      Hasil dari\u00a0(2x+3)(x\u22124)<\/span>(<\/span>2<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span>(<\/span>x<\/span>\u2212<\/span><\/span>4<\/span>)<\/span><\/span><\/span><\/span>\u00a0adalah …<\/p>\n

      Pembahasan:<\/strong><\/p>\n

        \n
      • \n

        (2x)(x)=2×2<\/span>(<\/span>2<\/span>x<\/span>)<\/span>(<\/span>x<\/span>)<\/span>=<\/span><\/span>2<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

      • \n

        (2x)(\u22124)=\u22128x<\/span>(<\/span>2<\/span>x<\/span>)<\/span>(<\/span>\u2212<\/span>4<\/span>)<\/span>=<\/span><\/span>\u2212<\/span>8<\/span>x<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

      • \n

        (3)(x)=3x<\/span>(<\/span>3<\/span>)<\/span>(<\/span>x<\/span>)<\/span>=<\/span><\/span>3<\/span>x<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

      • \n

        (3)(\u22124)=\u221212<\/span>(<\/span>3<\/span>)<\/span>(<\/span>\u2212<\/span>4<\/span>)<\/span>=<\/span><\/span>\u2212<\/span>12<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

      • \n

        Jumlahkan:\u00a02×2\u22128x+3x\u221212=2×2\u22125x\u221212<\/span>2<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>8<\/span>x<\/span>+<\/span><\/span>3<\/span>x<\/span>\u2212<\/span><\/span>12<\/span>=<\/span><\/span>2<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>5<\/span>x<\/span>\u2212<\/span><\/span>12<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

        Jawaban:\u00a02×2\u22125x\u221212<\/span>2<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>5<\/span>x<\/span>\u2212<\/span><\/span>12<\/span><\/span><\/span><\/span><\/strong><\/p>\n

        \n

        Soal 4 (Pemfaktoran dengan Faktor Persekutuan)<\/h3>\n

        Faktorkan\u00a06×2+9x<\/span>6<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>9<\/span>x<\/span><\/span><\/span><\/span><\/p>\n

        Pembahasan:<\/strong><\/p>\n

          \n
        • \n

          FPB dari 6 dan 9 = 3<\/p>\n<\/li>\n

        • \n

          Kedua suku memiliki variabel\u00a0x<\/span>x<\/span><\/span><\/span><\/span>\u00a0(pangkat terkecil = 1)<\/p>\n<\/li>\n

        • \n

          Faktor bersama =\u00a03x<\/span>3<\/span>x<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

        • \n

          6×2+9x=3x(2x+3)<\/span>6<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>9<\/span>x<\/span>=<\/span><\/span>3<\/span>x<\/span>(<\/span>2<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

          Jawaban:\u00a03x(2x+3)<\/span>3<\/span>x<\/span>(<\/span>2<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span><\/span><\/span><\/span><\/strong><\/p>\n

          \n

          Soal 5 (Menyederhanakan Pecahan Aljabar)<\/h3>\n

          Sederhanakan\u00a04×2+6x2x<\/span>2x<\/span><\/span><\/span>4x<\/span>2<\/span><\/span><\/span>+<\/span>6x<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u00a0(dengan\u00a0x\u22600<\/span>x<\/span>\ue020<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>0<\/span><\/span><\/span><\/span>)<\/p>\n

          Pembahasan:<\/strong><\/p>\n

            \n
          • \n

            Faktorkan pembilang:\u00a04×2+6x=2x(2x+3)<\/span>4<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>6<\/span>x<\/span>=<\/span><\/span>2<\/span>x<\/span>(<\/span>2<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

          • \n

            2x(2x+3)2x=2x+3<\/span>2x<\/span><\/span><\/span>2x<\/span>(<\/span>2x<\/span>+<\/span>3)<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span>x<\/span>+<\/span><\/span>3<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

            Jawaban:\u00a02x+3<\/span>2<\/span>x<\/span>+<\/span><\/span>3<\/span><\/span><\/span><\/span><\/strong><\/p>\n

            \n

            Soal 6 (Soal Tipe TKA \u2013 Faktorisasi dengan Distributif)<\/h3>\n

            Bentuk sederhana dari\u00a0(x+2)(3+y)+(x+2)(1\u2212y)<\/span>(<\/span>x<\/span>+<\/span><\/span>2<\/span>)<\/span>(<\/span>3<\/span>+<\/span><\/span>y<\/span>)<\/span>+<\/span><\/span>(<\/span>x<\/span>+<\/span><\/span>2<\/span>)<\/span>(<\/span>1<\/span>\u2212<\/span><\/span>y<\/span>)<\/span><\/span><\/span><\/span>\u00a0adalah …<\/p>\n

            Pembahasan:<\/strong><\/p>\n

              \n
            • \n

              Kedua suku memiliki faktor\u00a0(x+2)<\/span>(<\/span>x<\/span>+<\/span><\/span>2<\/span>)<\/span><\/span><\/span><\/span>\u00a0yang sama<\/p>\n<\/li>\n

            • \n

              (x+2)(3+y)+(x+2)(1\u2212y)=(x+2)[(3+y)+(1\u2212y)]<\/span>(<\/span>x<\/span>+<\/span><\/span>2<\/span>)<\/span>(<\/span>3<\/span>+<\/span><\/span>y<\/span>)<\/span>+<\/span><\/span>(<\/span>x<\/span>+<\/span><\/span>2<\/span>)<\/span>(<\/span>1<\/span>\u2212<\/span><\/span>y<\/span>)<\/span>=<\/span><\/span>(<\/span>x<\/span>+<\/span><\/span>2<\/span>)<\/span>[(<\/span>3<\/span>+<\/span><\/span>y<\/span>)<\/span>+<\/span><\/span>(<\/span>1<\/span>\u2212<\/span><\/span>y<\/span>)]<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

            • \n

              (3+y)+(1\u2212y)=3+y+1\u2212y=4<\/span>(<\/span>3<\/span>+<\/span><\/span>y<\/span>)<\/span>+<\/span><\/span>(<\/span>1<\/span>\u2212<\/span><\/span>y<\/span>)<\/span>=<\/span><\/span>3<\/span>+<\/span><\/span>y<\/span>+<\/span><\/span>1<\/span>\u2212<\/span><\/span>y<\/span>=<\/span><\/span>4<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

            • \n

              Hasil =\u00a04(x+2)<\/span>4<\/span>(<\/span>x<\/span>+<\/span><\/span>2<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

              Jawaban:\u00a04(x+2)<\/span>4<\/span>(<\/span>x<\/span>+<\/span><\/span>2<\/span>)<\/span><\/span><\/span><\/span><\/strong><\/p>\n

              \n

              Soal 7 (Operasi Campuran Penjumlahan & Pengurangan)<\/h3>\n

              Sederhanakan\u00a0(5x\u22122y)+(3x+4y)\u2212(2x\u2212y)<\/span>(<\/span>5<\/span>x<\/span>\u2212<\/span><\/span>2<\/span>y<\/span>)<\/span>+<\/span><\/span>(<\/span>3<\/span>x<\/span>+<\/span><\/span>4<\/span>y<\/span>)<\/span>\u2212<\/span><\/span>(<\/span>2<\/span>x<\/span>\u2212<\/span><\/span>y<\/span>)<\/span><\/span><\/span><\/span><\/p>\n

              Pembahasan:<\/strong><\/p>\n

                \n
              • \n

                (5x\u22122y)+(3x+4y)\u2212(2x\u2212y)=5x\u22122y+3x+4y\u22122x+y<\/span>(<\/span>5<\/span>x<\/span>\u2212<\/span><\/span>2<\/span>y<\/span>)<\/span>+<\/span><\/span>(<\/span>3<\/span>x<\/span>+<\/span><\/span>4<\/span>y<\/span>)<\/span>\u2212<\/span><\/span>(<\/span>2<\/span>x<\/span>\u2212<\/span><\/span>y<\/span>)<\/span>=<\/span><\/span>5<\/span>x<\/span>\u2212<\/span><\/span>2<\/span>y<\/span>+<\/span><\/span>3<\/span>x<\/span>+<\/span><\/span>4<\/span>y<\/span>\u2212<\/span><\/span>2<\/span>x<\/span>+<\/span><\/span>y<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

              • \n

                Kelompokkan suku sejenis:<\/p>\n

                  \n
                • \n

                  x<\/span>x<\/span><\/span><\/span><\/span>:\u00a05x+3x\u22122x=6x<\/span>5<\/span>x<\/span>+<\/span><\/span>3<\/span>x<\/span>\u2212<\/span><\/span>2<\/span>x<\/span>=<\/span><\/span>6<\/span>x<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                • \n

                  y<\/span>y<\/span><\/span><\/span><\/span>:\u00a0\u22122y+4y+y=3y<\/span>\u2212<\/span>2<\/span>y<\/span>+<\/span><\/span>4<\/span>y<\/span>+<\/span><\/span>y<\/span>=<\/span><\/span>3<\/span>y<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n<\/li>\n

                • \n

                  Hasil =\u00a06x+3y<\/span>6<\/span>x<\/span>+<\/span><\/span>3<\/span>y<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                  Jawaban:\u00a06x+3y<\/span>6<\/span>x<\/span>+<\/span><\/span>3<\/span>y<\/span><\/span><\/span><\/span><\/strong><\/p>\n

                  \n

                  Soal 8 (Pemfaktoran Bentuk\u00a0ax2+bx+c<\/span>a<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>b<\/span>x<\/span>+<\/span><\/span>c<\/span><\/span><\/span><\/span>)<\/h3>\n

                  Faktorkan\u00a0x2+7x+12<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>7<\/span>x<\/span>+<\/span><\/span>12<\/span><\/span><\/span><\/span><\/p>\n

                  Pembahasan:<\/strong><\/p>\n

                    \n
                  • \n

                    Cari dua bilangan yang:<\/p>\n

                      \n
                    • \n

                      Jumlah = 7<\/p>\n<\/li>\n

                    • \n

                      Hasil kali = 12<\/p>\n<\/li>\n<\/ul>\n<\/li>\n

                    • \n

                      Bilangan tersebut adalah 3 dan 4 (karena\u00a03+4=7<\/span>3<\/span>+<\/span><\/span>4<\/span>=<\/span><\/span>7<\/span><\/span><\/span><\/span>\u00a0dan\u00a03\u00d74=12<\/span>3<\/span>\u00d7<\/span><\/span>4<\/span>=<\/span><\/span>12<\/span><\/span><\/span><\/span>)<\/p>\n<\/li>\n

                    • \n

                      x2+7x+12=(x+3)(x+4)<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>7<\/span>x<\/span>+<\/span><\/span>12<\/span>=<\/span><\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span>(<\/span>x<\/span>+<\/span><\/span>4<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                      Jawaban:\u00a0(x+3)(x+4)<\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span>(<\/span>x<\/span>+<\/span><\/span>4<\/span>)<\/span><\/span><\/span><\/span><\/strong><\/p>\n

                      \n

                      Soal 9 (Kuadrat Jumlah)<\/h3>\n

                      Hasil dari\u00a0(2a\u22123b)2<\/span>(<\/span>2<\/span>a<\/span>\u2212<\/span><\/span>3<\/span>b<\/span>)2<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u00a0adalah …<\/p>\n

                      Pembahasan:<\/strong><\/p>\n

                        \n
                      • \n

                        (a\u2212b)2=a2\u22122ab+b2<\/span>(<\/span>a<\/span>\u2212<\/span><\/span>b<\/span>)2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>2<\/span>ab<\/span>+<\/span><\/span>b<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                      • \n

                        (2a\u22123b)2=(2a)2\u22122(2a)(3b)+(3b)2<\/span>(<\/span>2<\/span>a<\/span>\u2212<\/span><\/span>3<\/span>b<\/span>)2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>(<\/span>2<\/span>a<\/span>)2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>2<\/span>(<\/span>2<\/span>a<\/span>)<\/span>(<\/span>3<\/span>b<\/span>)<\/span>+<\/span><\/span>(<\/span>3<\/span>b<\/span>)2<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                      • \n

                        =4a2\u221212ab+9b2<\/span>=<\/span><\/span>4<\/span>a<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>12<\/span>ab<\/span>+<\/span><\/span>9<\/span>b<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                        Jawaban:\u00a04a2\u221212ab+9b2<\/span>4<\/span>a<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>12<\/span>ab<\/span>+<\/span><\/span>9<\/span>b<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/strong><\/p>\n

                        \n

                        Soal 10 (Selisih Kuadrat)<\/h3>\n

                        Sederhanakan\u00a0x2\u22129x\u22123<\/span>x<\/span>\u2212<\/span>3<\/span><\/span>x<\/span>2<\/span><\/span><\/span>\u2212<\/span>9<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u00a0(dengan\u00a0x\u22603<\/span>x<\/span>\ue020<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>3<\/span><\/span><\/span><\/span>)<\/p>\n

                        Pembahasan:<\/strong><\/p>\n

                          \n
                        • \n

                          x2\u22129=(x\u22123)(x+3)<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>9<\/span>=<\/span><\/span>(<\/span>x<\/span>\u2212<\/span><\/span>3<\/span>)<\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span><\/span><\/span><\/span>\u00a0(selisih kuadrat)<\/p>\n<\/li>\n

                        • \n

                          (x\u22123)(x+3)x\u22123=x+3<\/span>x<\/span>\u2212<\/span>3<\/span><\/span>(<\/span>x<\/span>\u2212<\/span>3)<\/span>(<\/span>x<\/span>+<\/span>3)<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>x<\/span>+<\/span><\/span>3<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                          Jawaban:\u00a0x+3<\/span>x<\/span>+<\/span><\/span>3<\/span><\/span><\/span><\/span><\/strong><\/p>\n

                          \n

                          Soal 11 (Penerapan Sifat Komutatif)<\/h3>\n

                          Manakah bentuk yang SETARA dengan\u00a03x\u00d74y<\/span>3<\/span>x<\/span>\u00d7<\/span><\/span>4<\/span>y<\/span><\/span><\/span><\/span>?<\/p>\n

                          Pembahasan:<\/strong><\/p>\n

                            \n
                          • \n

                            Sifat komutatif perkalian:\u00a03x\u00d74y=3\u00d74\u00d7x\u00d7y=12xy<\/span>3<\/span>x<\/span>\u00d7<\/span><\/span>4<\/span>y<\/span>=<\/span><\/span>3<\/span>\u00d7<\/span><\/span>4<\/span>\u00d7<\/span><\/span>x<\/span>\u00d7<\/span><\/span>y<\/span>=<\/span><\/span>12<\/span>x<\/span>y<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                          • \n

                            Bentuk setara:\u00a04y\u00d73x<\/span>4<\/span>y<\/span>\u00d7<\/span><\/span>3<\/span>x<\/span><\/span><\/span><\/span>,\u00a012xy<\/span>12<\/span>x<\/span>y<\/span><\/span><\/span><\/span>,\u00a0y\u00d712x<\/span>y<\/span>\u00d7<\/span><\/span>12<\/span>x<\/span><\/span><\/span><\/span>,\u00a04\u00d73\u00d7x\u00d7y<\/span>4<\/span>\u00d7<\/span><\/span>3<\/span>\u00d7<\/span><\/span>x<\/span>\u00d7<\/span><\/span>y<\/span><\/span><\/span><\/span>, dll.<\/p>\n<\/li>\n<\/ul>\n

                            Jawaban:\u00a012xy<\/span>12<\/span>x<\/span>y<\/span><\/span><\/span><\/span>\u00a0atau\u00a04y\u00d73x<\/span>4<\/span>y<\/span>\u00d7<\/span><\/span>3<\/span>x<\/span><\/span><\/span><\/span><\/strong><\/p>\n

                            \n

                            Soal 12 (Penerapan Sifat Asosiatif)<\/h3>\n

                            Bentuk\u00a0(2a+3b)+(4a\u2212b)<\/span>(<\/span>2<\/span>a<\/span>+<\/span><\/span>3<\/span>b<\/span>)<\/span>+<\/span><\/span>(<\/span>4<\/span>a<\/span>\u2212<\/span><\/span>b<\/span>)<\/span><\/span><\/span><\/span>\u00a0sama dengan ….<\/p>\n

                            Pembahasan:<\/strong><\/p>\n

                              \n
                            • \n

                              Dengan sifat asosiatif:\u00a0(2a+3b)+(4a\u2212b)=2a+3b+4a\u2212b<\/span>(<\/span>2<\/span>a<\/span>+<\/span><\/span>3<\/span>b<\/span>)<\/span>+<\/span><\/span>(<\/span>4<\/span>a<\/span>\u2212<\/span><\/span>b<\/span>)<\/span>=<\/span><\/span>2<\/span>a<\/span>+<\/span><\/span>3<\/span>b<\/span>+<\/span><\/span>4<\/span>a<\/span>\u2212<\/span><\/span>b<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                            • \n

                              Kelompokkan:\u00a0(2a+4a)+(3b\u2212b)=6a+2b<\/span>(<\/span>2<\/span>a<\/span>+<\/span><\/span>4<\/span>a<\/span>)<\/span>+<\/span><\/span>(<\/span>3<\/span>b<\/span>\u2212<\/span><\/span>b<\/span>)<\/span>=<\/span><\/span>6<\/span>a<\/span>+<\/span><\/span>2<\/span>b<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                              Jawaban:\u00a06a+2b<\/span>6<\/span>a<\/span>+<\/span><\/span>2<\/span>b<\/span><\/span><\/span><\/span><\/strong><\/p>\n

                              \n

                              Soal 13 (Perkalian dengan Tiga Suku)<\/h3>\n

                              Hasil dari\u00a0(x+2)(x\u22123)(x+1)<\/span>(<\/span>x<\/span>+<\/span><\/span>2<\/span>)<\/span>(<\/span>x<\/span>\u2212<\/span><\/span>3<\/span>)<\/span>(<\/span>x<\/span>+<\/span><\/span>1<\/span>)<\/span><\/span><\/span><\/span>\u00a0adalah …<\/p>\n

                              Pembahasan:<\/strong><\/p>\n

                                \n
                              • \n

                                Kalikan dua suku pertama:\u00a0(x+2)(x\u22123)=x2\u22123x+2x\u22126=x2\u2212x\u22126<\/span>(<\/span>x<\/span>+<\/span><\/span>2<\/span>)<\/span>(<\/span>x<\/span>\u2212<\/span><\/span>3<\/span>)<\/span>=<\/span><\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>3<\/span>x<\/span>+<\/span><\/span>2<\/span>x<\/span>\u2212<\/span><\/span>6<\/span>=<\/span><\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>x<\/span>\u2212<\/span><\/span>6<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                              • \n

                                Kalikan hasil dengan\u00a0(x+1)<\/span>(<\/span>x<\/span>+<\/span><\/span>1<\/span>)<\/span><\/span><\/span><\/span>:<\/p>\n

                                  \n
                                • \n

                                  (x2)(x)=x3<\/span>(<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>)<\/span>(<\/span>x<\/span>)<\/span>=<\/span><\/span>x<\/span>3<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                                • \n

                                  (x2)(1)=x2<\/span>(<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>)<\/span>(<\/span>1<\/span>)<\/span>=<\/span><\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                                • \n

                                  (\u2212x)(x)=\u2212x2<\/span>(<\/span>\u2212<\/span>x<\/span>)<\/span>(<\/span>x<\/span>)<\/span>=<\/span><\/span>\u2212<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                                • \n

                                  (\u2212x)(1)=\u2212x<\/span>(<\/span>\u2212<\/span>x<\/span>)<\/span>(<\/span>1<\/span>)<\/span>=<\/span><\/span>\u2212<\/span>x<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                                • \n

                                  (\u22126)(x)=\u22126x<\/span>(<\/span>\u2212<\/span>6<\/span>)<\/span>(<\/span>x<\/span>)<\/span>=<\/span><\/span>\u2212<\/span>6<\/span>x<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                                • \n

                                  (\u22126)(1)=\u22126<\/span>(<\/span>\u2212<\/span>6<\/span>)<\/span>(<\/span>1<\/span>)<\/span>=<\/span><\/span>\u2212<\/span>6<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n<\/li>\n

                                • \n

                                  Jumlahkan:\u00a0x3+(x2\u2212x2)+(\u2212x\u22126x)\u22126=x3\u22127x\u22126<\/span>x<\/span>3<\/span><\/span><\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>(<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>)<\/span>+<\/span><\/span>(<\/span>\u2212<\/span>x<\/span>\u2212<\/span><\/span>6<\/span>x<\/span>)<\/span>\u2212<\/span><\/span>6<\/span>=<\/span><\/span>x<\/span>3<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>7<\/span>x<\/span>\u2212<\/span><\/span>6<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                                  Jawaban:\u00a0x3\u22127x\u22126<\/span>x<\/span>3<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>7<\/span>x<\/span>\u2212<\/span><\/span>6<\/span><\/span><\/span><\/span><\/strong><\/p>\n

                                  \n

                                  Soal 14 (Menyederhanakan dengan Faktorisasi)<\/h3>\n

                                  Bentuk sederhana dari\u00a02×2\u22128x\u22122<\/span>x<\/span>\u2212<\/span>2<\/span><\/span>2x<\/span>2<\/span><\/span><\/span>\u2212<\/span>8<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u00a0(dengan\u00a0x\u22602<\/span>x<\/span>\ue020<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span><\/span><\/span><\/span>) adalah …<\/p>\n

                                  Pembahasan:<\/strong><\/p>\n

                                    \n
                                  • \n

                                    Faktorkan pembilang:\u00a02×2\u22128=2(x2\u22124)=2(x\u22122)(x+2)<\/span>2<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>8<\/span>=<\/span><\/span>2<\/span>(<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>4<\/span>)<\/span>=<\/span><\/span>2<\/span>(<\/span>x<\/span>\u2212<\/span><\/span>2<\/span>)<\/span>(<\/span>x<\/span>+<\/span><\/span>2<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                                  • \n

                                    2(x\u22122)(x+2)x\u22122=2(x+2)=2x+4<\/span>x<\/span>\u2212<\/span>2<\/span><\/span>2(<\/span>x<\/span>\u2212<\/span>2)<\/span>(<\/span>x<\/span>+<\/span>2)<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span>(<\/span>x<\/span>+<\/span><\/span>2<\/span>)<\/span>=<\/span><\/span>2<\/span>x<\/span>+<\/span><\/span>4<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                                    Jawaban:\u00a02x+4<\/span>2<\/span>x<\/span>+<\/span><\/span>4<\/span><\/span><\/span><\/span><\/strong><\/p>\n

                                    \n

                                    Soal 15 (Soal Tipe TKA \u2013 Distributif dengan Dua Kelompok)<\/h3>\n

                                    Sederhanakan\u00a0(x+3)(2+y)+(x+3)(1\u2212y)<\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span>(<\/span>2<\/span>+<\/span><\/span>y<\/span>)<\/span>+<\/span><\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span>(<\/span>1<\/span>\u2212<\/span><\/span>y<\/span>)<\/span><\/span><\/span><\/span><\/p>\n

                                    Pembahasan:<\/strong><\/p>\n

                                      \n
                                    • \n

                                      Kedua suku memiliki faktor\u00a0(x+3)<\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span><\/span><\/span><\/span>\u00a0yang sama<\/p>\n<\/li>\n

                                    • \n

                                      (x+3)(2+y)+(x+3)(1\u2212y)=(x+3)[(2+y)+(1\u2212y)]<\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span>(<\/span>2<\/span>+<\/span><\/span>y<\/span>)<\/span>+<\/span><\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span>(<\/span>1<\/span>\u2212<\/span><\/span>y<\/span>)<\/span>=<\/span><\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span>[(<\/span>2<\/span>+<\/span><\/span>y<\/span>)<\/span>+<\/span><\/span>(<\/span>1<\/span>\u2212<\/span><\/span>y<\/span>)]<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                                    • \n

                                      (2+y)+(1\u2212y)=2+y+1\u2212y=3<\/span>(<\/span>2<\/span>+<\/span><\/span>y<\/span>)<\/span>+<\/span><\/span>(<\/span>1<\/span>\u2212<\/span><\/span>y<\/span>)<\/span>=<\/span><\/span>2<\/span>+<\/span><\/span>y<\/span>+<\/span><\/span>1<\/span>\u2212<\/span><\/span>y<\/span>=<\/span><\/span>3<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n

                                    • \n

                                      Hasil =\u00a03(x+3)<\/span>3<\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span><\/span><\/span><\/span><\/p>\n<\/li>\n<\/ul>\n

                                      Jawaban:\u00a03(x+3)<\/span>3<\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span><\/span><\/span><\/span><\/strong><\/p>\n

                                      Ringkasan Rumus Penting Bentuk Aljabar<\/h2>\n
                                      \n
                                      \n
                                      <\/div>\n<\/div>\n\n\n\n\n\n\n\n\n\n\n
                                      Operasi<\/th>\nRumus<\/th>\nContoh<\/th>\n<\/tr>\n<\/thead>\n
                                      Penjumlahan<\/td>\nHanya suku sejenis<\/td>\n3x+2x=5x<\/span>3<\/span>x<\/span>+<\/span><\/span>2<\/span>x<\/span>=<\/span><\/span>5<\/span>x<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n
                                      Perkalian distributif<\/td>\na(b+c)=ab+ac<\/span>a<\/span>(<\/span>b<\/span>+<\/span><\/span>c<\/span>)<\/span>=<\/span><\/span>ab<\/span>+<\/span><\/span>a<\/span>c<\/span><\/span><\/span><\/span><\/td>\n2(x+3)=2x+6<\/span>2<\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span>=<\/span><\/span>2<\/span>x<\/span>+<\/span><\/span>6<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n
                                      Perkalian dua suku<\/td>\n(a+b)(c+d)=ac+ad+bc+bd<\/span>(<\/span>a<\/span>+<\/span><\/span>b<\/span>)<\/span>(<\/span>c<\/span>+<\/span><\/span>d<\/span>)<\/span>=<\/span><\/span>a<\/span>c<\/span>+<\/span><\/span>a<\/span>d<\/span>+<\/span><\/span>b<\/span>c<\/span>+<\/span><\/span>b<\/span>d<\/span><\/span><\/span><\/span><\/td>\n(x+2)(x+3)=x2+5x+6<\/span>(<\/span>x<\/span>+<\/span><\/span>2<\/span>)<\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span>=<\/span><\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>5<\/span>x<\/span>+<\/span><\/span>6<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n
                                      Selisih kuadrat<\/td>\na2\u2212b2=(a\u2212b)(a+b)<\/span>a<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>b<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>(<\/span>a<\/span>\u2212<\/span><\/span>b<\/span>)<\/span>(<\/span>a<\/span>+<\/span><\/span>b<\/span>)<\/span><\/span><\/span><\/span><\/td>\nx2\u22129=(x\u22123)(x+3)<\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>9<\/span>=<\/span><\/span>(<\/span>x<\/span>\u2212<\/span><\/span>3<\/span>)<\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n
                                      Kuadrat jumlah<\/td>\n(a+b)2=a2+2ab+b2<\/span>(<\/span>a<\/span>+<\/span><\/span>b<\/span>)2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>2<\/span>ab<\/span>+<\/span><\/span>b<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/td>\n(x+3)2=x2+6x+9<\/span>(<\/span>x<\/span>+<\/span><\/span>3<\/span>)2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>6<\/span>x<\/span>+<\/span><\/span>9<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n
                                      Kuadrat selisih<\/td>\n(a\u2212b)2=a2\u22122ab+b2<\/span>(<\/span>a<\/span>\u2212<\/span><\/span>b<\/span>)2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>2<\/span>ab<\/span>+<\/span><\/span>b<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/td>\n(x\u22123)2=x2\u22126x+9<\/span>(<\/span>x<\/span>\u2212<\/span><\/span>3<\/span>)2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>x<\/span>2<\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>6<\/span>x<\/span>+<\/span><\/span>9<\/span><\/span><\/span><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n
                                      \n

                                      Sahabat Rumah Pintar, dengan menguasai 15 soal di atas, kalian sudah siap menyederhanakan, memfaktorkan, dan memanipulasi berbagai bentuk aljabar di TKA Matematika SMP. Ingat kuncinya:\u00a0suku sejenis hanya bisa dijumlah\/dikurang, perhatikan tanda negatif saat distributif, dan hafal rumus perkalian serta pemfaktoran. Terus berlatih, ya!\u00a0Tetap pintar, tetap santai!<\/p>\n","protected":false},"excerpt":{"rendered":"

                                      Bimbel Rumah Pintar\u00a0\u2013\u00a0Sahabat Rumah Pintar, memecahkan soal bentuk aljabar dan sifat operasinya tentu wajib bisa Kamu lakukan untuk sukses di TKA Matematika SMP. Perlu diketahui, bentuk aljabar adalah kalimat matematika yang memuat variabel (huruf pengganti bilangan yang belum diketahui), koefisien […]<\/p>\n","protected":false},"author":1,"featured_media":2105,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"set","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[4],"tags":[218,223,219,221,220,222,224,207],"class_list":["post-2104","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-bahas-soal","tag-bentuk-aljabar","tag-contoh-soal-aljabar","tag-komutatif-asosiatif-distributif","tag-pemfaktoran","tag-penyederhanaan-aljabar","tag-perkalian-aljabar","tag-soal-tka-matematika-smp","tag-tka-matematika-smp"],"_links":{"self":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2104","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/comments?post=2104"}],"version-history":[{"count":2,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2104\/revisions"}],"predecessor-version":[{"id":2107,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2104\/revisions\/2107"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/media\/2105"}],"wp:attachment":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/media?parent=2104"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/categories?post=2104"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/tags?post=2104"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}