{"id":2068,"date":"2026-04-03T07:15:27","date_gmt":"2026-04-03T07:15:27","guid":{"rendered":"https:\/\/rumahpintar.co.id\/blog\/?p=2068"},"modified":"2026-04-08T08:13:45","modified_gmt":"2026-04-08T08:13:45","slug":"soal-estimasi-hasil-perhitungan-bilangan-real","status":"publish","type":"post","link":"https:\/\/rumahpintar.co.id\/blog\/soal-estimasi-hasil-perhitungan-bilangan-real\/","title":{"rendered":"Cara Cepat dan Bedah Soal Estimasi Hasil Perhitungan Bilangan Real Soal TKA SMP"},"content":{"rendered":"
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Bimbel Rumah Pintar<\/strong><\/a> – Sahabat Rumah Pintar, menyelesaikan soal estimasi hasil perhitungan adalah keterampilan membulatkan bilangan lalu melakukan operasi hitung sederhana untuk mendapatkan hasil yang “mendekati” nilai sebenarnya, tanpa menghitung secara tepat. Prinsip utamanya adalah pembulatan yang cerdas: angka < 5 dibulatkan ke bawah, angka \u2265 5 dibulatkan ke atas.<\/p>\n

Selain itu, kenali tiga jenis taksiran:\u00a0taksiran tinggi\u00a0(semua dibulatkan ke atas),\u00a0taksiran rendah\u00a0(semua dibulatkan ke bawah), dan\u00a0taksiran terbaik\u00a0(pembulatan ke nilai terdekat). Kemampuan ini sangat berguna untuk mengecek kewajaran hasil hitungan, menjawab soal dengan cepat saat ujian, serta membuat keputusan sehari-hari seperti memperkirakan total belanja.<\/p>\n

Mengapa latihan soal estimasi sangat penting?\u00a0Soal TKA Matematika SMP sering menyajikan soal estimasi dalam bentuk cerita (perkiraan total harga, perkiraan diskon, perkiraan hasil operasi) dengan pilihan ganda kompleks (PGK) yang menuntut siswa memilih semua pernyataan yang benar.<\/p>\n

Tanpa latihan yang cukup, banyak siswa terjebak membulatkan terlalu kasar atau lupa menyesuaikan arah pembulatan. Dengan menguasai 15 variasi soal berikut, Sahabat Rumah Pintar akan mampu menentukan perkiraan yang paling mendekati, menilai apakah suatu estimasi masuk akal, dan menjawab soal TKA<\/a> dengan percaya diri.<\/p>\n

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15 Contoh Soal Estimasi Hasil Perhitungan Bilangan Real dan Pembahasannya<\/h2>\n

Soal 1<\/h3>\n

Perkirakan hasil dari\u00a04.876+3.219+2.543<\/span>4.876<\/span>+<\/span><\/span>3.219<\/span>+<\/span><\/span>2.543<\/span><\/span><\/span><\/span>\u00a0dengan pembulatan ke ratusan terdekat!<\/p>\n

Pembahasan:<\/strong>
\nBulatkan setiap bilangan ke ratusan terdekat:<\/p>\n

    \n
  • \n

    4.876 \u2192 angka puluhan = 7 (\u22655) \u2192 4.900<\/p>\n<\/li>\n

  • \n

    3.219 \u2192 angka puluhan = 1 (<5) \u2192 3.200<\/p>\n<\/li>\n

  • \n

    2.543 \u2192 angka puluhan = 4 (<5) \u2192 2.500
    \nJumlah = 4.900 + 3.200 + 2.500 =\u00a010.600<\/strong>
    \nHasil sebenarnya = 10.638 \u2192 estimasi sangat baik.<\/p>\n<\/li>\n<\/ul>\n

    \n

    Soal 2<\/h3>\n

    Seorang pembeli membeli 19,6 kg beras seharga Rp12.750 per kg. Manakah pernyataan yang BENAR tentang perkiraan total harga? (PGK)
    \nA. Kurang dari Rp260.000
    \nB. Lebih besar dari Rp240.000
    \nC. Mendekati Rp230.000
    \nD. Dapat diperkirakan dengan 20 \u00d7 12.500<\/p>\n

    Pembahasan:<\/strong><\/p>\n

      \n
    • \n

      Taksiran tinggi: 20 \u00d7 13.000 = 260.000 \u2192 A benar<\/p>\n<\/li>\n

    • \n

      Taksiran rendah: 19 \u00d7 12.000 = 228.000 \u2192 B benar (karena hasil sebenarnya sekitar 250.000)<\/p>\n<\/li>\n

    • \n

      Hasil sebenarnya \u2248 19,6 \u00d7 12.750 = 249.900 \u2192 tidak mendekati 230.000 \u2192 C salah<\/p>\n<\/li>\n

    • \n

      20 \u00d7 12.500 = 250.000 \u2192 D benar
      \nJawaban: A, B, D<\/strong><\/p>\n<\/li>\n<\/ul>\n

      \n

      Soal 3<\/h3>\n

      Perkirakan hasil dari\u00a087\u00d7214<\/span>87<\/span>\u00d7<\/span><\/span>214<\/span><\/span><\/span><\/span>\u00a0dengan pembulatan ke puluhan terdekat!<\/p>\n

      Pembahasan:<\/strong><\/p>\n

        \n
      • \n

        87 \u2192 puluhan terdekat = 90 (karena 7 \u2265 5)<\/p>\n<\/li>\n

      • \n

        214 \u2192 puluhan terdekat = 210 (karena 4 < 5)
        \nHasil estimasi = 90 \u00d7 210 =\u00a018.900<\/strong>
        \nHasil sebenarnya = 18.618 \u2192 estimasi cukup baik.<\/p>\n<\/li>\n<\/ul>\n

        \n

        Soal 4<\/h3>\n

        Apakah pernyataan “87\u00d7214\u224818.000<\/span>87<\/span>\u00d7<\/span><\/span>214<\/span>\u2248<\/span><\/span>18.000<\/span><\/span><\/span><\/span>” merupakan estimasi yang masuk akal?<\/p>\n

        Pembahasan:<\/strong>
        \n87 \u2248 90, 214 \u2248 200 \u2192 90 \u00d7 200 = 18.000
        \nHasil sebenarnya = 18.618
        \nSelisih = 618 dari 18.618 \u2248 3,3% \u2192 masih dalam batas wajar.
        \nJawaban: Ya, masuk akal sebagai estimasi kasar.<\/strong><\/p>\n

        \n

        Soal 5<\/h3>\n

        Perkirakan hasil dari\u00a01.250\u00f724<\/span>1.250<\/span>\u00f7<\/span><\/span>24<\/span><\/span><\/span><\/span>\u00a0dengan pembulatan pembagi ke bilangan yang mudah!<\/p>\n

        Pembahasan:<\/strong>
        \n24 dibulatkan menjadi 25 (bilangan mudah)
        \n1.250 \u00f7 25 =\u00a050<\/strong>
        \nHasil sebenarnya = 52,08 \u2192 estimasi 50 cukup baik.<\/p>\n

        \n

        Soal 6<\/h3>\n

        Sebuah toko memberikan diskon 19,8% untuk barang seharga Rp249.500. Perkirakan besar diskon yang diperoleh!<\/p>\n

        Pembahasan:<\/strong><\/p>\n

          \n
        • \n

          19,8% \u2248 20%<\/p>\n<\/li>\n

        • \n

          Rp249.500 \u2248 Rp250.000
          \n20% \u00d7 250.000 =\u00a0Rp50.000<\/strong>
          \nHasil sebenarnya = 19,8% \u00d7 249.500 = Rp49.401 \u2192 estimasi sangat baik.<\/p>\n<\/li>\n<\/ul>\n

          \n

          Soal 7<\/h3>\n

          Perkirakan hasil dari\u00a02.345+1.876\u2212987<\/span>2.345<\/span>+<\/span><\/span>1.876<\/span>\u2212<\/span><\/span>987<\/span><\/span><\/span><\/span>\u00a0dengan pembulatan ke ratusan terdekat!<\/p>\n

          Pembahasan:<\/strong><\/p>\n

            \n
          • \n

            2.345 \u2192 2.300 (puluhan 4 < 5)<\/p>\n<\/li>\n

          • \n

            1.876 \u2192 1.900 (puluhan 7 \u2265 5)<\/p>\n<\/li>\n

          • \n

            987 \u2192 1.000 (puluhan 8 \u2265 5)
            \nHasil = 2.300 + 1.900 – 1.000 =\u00a03.200<\/strong>
            \nHasil sebenarnya = 3.234 \u2192 estimasi baik.<\/p>\n<\/li>\n<\/ul>\n

            \n

            Soal 8<\/h3>\n

            Manakah perkiraan yang PALING mendekati hasil\u00a05.678\u00d71.234<\/span>5.678<\/span>\u00d7<\/span><\/span>1.234<\/span><\/span><\/span><\/span>?
            \nA. 5.000 \u00d7 1.000 = 5.000.000
            \nB. 6.000 \u00d7 1.200 = 7.200.000
            \nC. 5.700 \u00d7 1.200 = 6.840.000<\/p>\n

            Pembahasan:<\/strong>
            \nHasil sebenarnya = 5.678 \u00d7 1.234 \u2248 7.006.000<\/p>\n

              \n
            • \n

              A: 5.000.000 (selisih 2.006.000)<\/p>\n<\/li>\n

            • \n

              B: 7.200.000 (selisih 194.000)<\/p>\n<\/li>\n

            • \n

              C: 6.840.000 (selisih 166.000)
              \nYang paling mendekati adalah\u00a0C<\/strong>\u00a0(selisih terkecil = 166.000)<\/p>\n<\/li>\n<\/ul>\n

              \n

              Soal 9<\/h3>\n

              Harga 1 buah apel Rp2.750. Jika membeli 47 apel, perkirakan total harga dengan pembulatan ke ribuan dan puluhan!<\/p>\n

              Pembahasan:<\/strong><\/p>\n

                \n
              • \n

                Rp2.750 \u2248 Rp3.000 (ke ribuan)<\/p>\n<\/li>\n

              • \n

                47 \u2248 50
                \nEstimasi = 3.000 \u00d7 50 =\u00a0Rp150.000<\/strong>
                \nHasil sebenarnya = 2.750 \u00d7 47 = Rp129.250 \u2192 estimasi taksiran tinggi.<\/p>\n<\/li>\n<\/ul>\n

                \n

                Soal 10<\/h3>\n

                Sebuah kue dipotong menjadi 8 bagian. Jika 3 potong sudah dimakan, perkirakan bagian yang tersisa dalam bentuk pecahan!<\/p>\n

                Pembahasan:<\/strong>
                \nSisa potongan = 8 – 3 = 5 potong dari 8 =\u00a058<\/span>8<\/span><\/span>5<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>
                \nEstimasi:\u00a058=0,625<\/span>8<\/span><\/span>5<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>0<\/span>,<\/span>625<\/span><\/span><\/span><\/span>\u00a0\u2192 mendekati\u00a00,6<\/strong>\u00a0atau\u00a035<\/span>5<\/span><\/span>3<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/strong>\u00a0atau\u00a023<\/span>3<\/span><\/span>2<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/strong>\u00a0tergantung konteks.
                \nEstimasi terbaik =\u00a012<\/span>2<\/span><\/span>1<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u00a0lebih sedikit<\/strong>\u00a0atau\u00a034<\/span>4<\/span><\/span>3<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u00a0kurang sedikit<\/strong>.<\/p>\n

                \n

                Soal 11<\/h3>\n

                Perkirakan hasil dari\u00a012.345+23.456+34.567<\/span>12.345<\/span>+<\/span><\/span>23.456<\/span>+<\/span><\/span>34.567<\/span><\/span><\/span><\/span>\u00a0dengan pembulatan ke ribuan terdekat!<\/p>\n

                Pembahasan:<\/strong><\/p>\n

                  \n
                • \n

                  12.345 \u2192 12.000 (ratusan 3 < 5)<\/p>\n<\/li>\n

                • \n

                  23.456 \u2192 23.000 (ratusan 4 < 5)<\/p>\n<\/li>\n

                • \n

                  34.567 \u2192 35.000 (ratusan 5 \u2265 5)
                  \nJumlah = 12.000 + 23.000 + 35.000 =\u00a070.000<\/strong>
                  \nHasil sebenarnya = 70.368 \u2192 estimasi sangat baik.<\/p>\n<\/li>\n<\/ul>\n

                  \n

                  Soal 12<\/h3>\n

                  Seorang pedagang membeli 58 kg mangga seharga Rp4.250 per kg. Perkirakan total harga menggunakan taksiran rendah!<\/p>\n

                  Pembahasan:<\/strong>
                  \nTaksiran rendah = bulatkan semua ke bawah:<\/p>\n

                    \n
                  • \n

                    58 \u2192 50<\/p>\n<\/li>\n

                  • \n

                    Rp4.250 \u2192 Rp4.000
                    \nEstimasi = 50 \u00d7 4.000 =\u00a0Rp200.000<\/strong>
                    \nHasil sebenarnya = 58 \u00d7 4.250 = Rp246.500 \u2192 taksiran rendah lebih kecil dari asli.<\/p>\n<\/li>\n<\/ul>\n

                    \n

                    Soal 13<\/h3>\n

                    Jika 1 liter bensin Rp9.800 dan mobil membutuhkan 23,7 liter, perkirakan biaya bensin dengan dua cara: (a) 20 \u00d7 10.000, (b) 24 \u00d7 10.000. Mana yang lebih baik?<\/p>\n

                    Pembahasan:<\/strong>
                    \nHasil sebenarnya = 9.800 \u00d7 23,7 = Rp232.260<\/p>\n

                      \n
                    • \n

                      Cara (a): 20 \u00d7 10.000 = 200.000 (selisih 32.260)<\/p>\n<\/li>\n

                    • \n

                      Cara (b): 24 \u00d7 10.000 = 240.000 (selisih 7.740)
                      \nCara (b)\u00a0lebih baik<\/strong>\u00a0karena selisih lebih kecil.<\/p>\n<\/li>\n<\/ul>\n

                      \n

                      Soal 14<\/h3>\n

                      Manakah pernyataan yang BENAR tentang estimasi\u00a03.456\u00f71.234<\/span>3.456<\/span>\u00f7<\/span><\/span>1.234<\/span><\/span><\/span><\/span>?
                      \nA. Hasil kurang dari 3
                      \nB. Hasil lebih dari 2,5
                      \nC. Hasil mendekati 2,8
                      \nD. Dapat diperkirakan dengan 3.500 \u00f7 1.200<\/p>\n

                      Pembahasan:<\/strong>
                      \nHasil sebenarnya \u2248 2,80<\/p>\n

                        \n
                      • \n

                        A: 2,80 < 3 \u2192 benar<\/p>\n<\/li>\n

                      • \n

                        B: 2,80 > 2,5 \u2192 benar<\/p>\n<\/li>\n

                      • \n

                        C: mendekati 2,8 \u2192 benar<\/p>\n<\/li>\n

                      • \n

                        D: 3.500 \u00f7 1.200 \u2248 2,92 (masih mendekati) \u2192 benar
                        \nJawaban: A, B, C, D (semua benar)<\/strong><\/p>\n<\/li>\n<\/ul>\n

                        \n

                        Soal 15<\/h3>\n

                        Perkirakan hasil dari\u00a058+712\u221213<\/span>8<\/span><\/span>5<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>12<\/span><\/span>7<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>3<\/span><\/span>1<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u00a0dengan mengubah setiap pecahan ke estimasi desimal terdekat (0; 0,5; atau 1)!<\/p>\n

                        Pembahasan:<\/strong><\/p>\n

                          \n
                        • \n

                          58=0,625<\/span>8<\/span><\/span>5<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>0<\/span>,<\/span>625<\/span><\/span><\/span><\/span>\u00a0\u2192 mendekati 0,5 atau 1? lebih dekat ke 0,5? Sebenarnya 0,625 lebih dekat ke 0,5? Hitung: 0,625 – 0,5 = 0,125; 1 – 0,625 = 0,375 \u2192 lebih dekat ke 0,5<\/p>\n<\/li>\n

                        • \n

                          712\u22480,583<\/span>12<\/span><\/span>7<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u2248<\/span><\/span>0<\/span>,<\/span>583<\/span><\/span><\/span><\/span>\u00a0\u2192 mendekati 0,5<\/p>\n<\/li>\n

                        • \n

                          13\u22480,333<\/span>3<\/span><\/span>1<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u2248<\/span><\/span>0<\/span>,<\/span>333<\/span><\/span><\/span><\/span>\u00a0\u2192 mendekati 0,5? 0,333 lebih dekat ke 0,5? Jarak ke 0 = 0,333; ke 0,5 = 0,167; ke 1 = 0,667 \u2192 lebih dekat ke 0,5
                          \nEstimasi = 0,5 + 0,5 – 0,5 =\u00a00,5<\/strong>
                          \nHasil sebenarnya =\u00a058+712\u221213=1524+1424\u2212824=2124=78=0,875<\/span>8<\/span><\/span>5<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>12<\/span><\/span>7<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>3<\/span><\/span>1<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>24<\/span><\/span>15<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>24<\/span><\/span>14<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>24<\/span><\/span>8<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>24<\/span><\/span>21<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>8<\/span><\/span>7<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>0<\/span>,<\/span>875<\/span><\/span><\/span><\/span>\u00a0\u2192 estimasi 0,5 kurang baik, lebih baik pakai estimasi 1 + 0,5 – 0,5 = 1.<\/p>\n<\/li>\n<\/ul>\n

                          \n

                          Penutup<\/h2>\n

                          Sahabat Rumah Pintar<\/strong>, menguasai\u00a0estimasi bilangan real<\/strong>\u00a0akan sangat membantu dalam menyelesaikan soal TKA Matematika SMP dengan cepat dan tepat. Ingat selalu:<\/p>\n

                            \n
                          • \n

                            Pahami aturan pembulatan (angka <5 ke bawah, \u22655 ke atas)<\/p>\n<\/li>\n

                          • \n

                            Kenali taksiran tinggi, rendah, dan terbaik<\/p>\n<\/li>\n

                          • \n

                            Untuk PGK, periksa semua pernyataan satu per satu<\/p>\n<\/li>\n

                          • \n

                            Latih estimasi perkalian dengan angka bulat seperti 10, 20, 50, 100, 200<\/p>\n<\/li>\n<\/ul>\n

                            Terus berlatih, ya! Rumah Pintar selalu mendukung perjalanan belajarmu.\u00a0Tetap pintar, tetap santai!<\/strong>\u00a0\ud83d\ude0a<\/p>\n<\/div>\n<\/div>\n

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                            <\/div>\n
                            <\/div>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

                            Bimbel Rumah Pintar – Sahabat Rumah Pintar, menyelesaikan soal estimasi hasil perhitungan adalah keterampilan membulatkan bilangan lalu melakukan operasi hitung sederhana untuk mendapatkan hasil yang “mendekati” nilai sebenarnya, tanpa menghitung secara tepat. Prinsip utamanya adalah pembulatan yang cerdas: angka < […]<\/p>\n","protected":false},"author":1,"featured_media":2070,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"set","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[4],"tags":[209,206,207],"class_list":["post-2068","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-bahas-soal","tag-estimasi-hasil-hitung","tag-soal-tka-smp","tag-tka-matematika-smp"],"_links":{"self":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2068","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/comments?post=2068"}],"version-history":[{"count":3,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2068\/revisions"}],"predecessor-version":[{"id":2075,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/posts\/2068\/revisions\/2075"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/media\/2070"}],"wp:attachment":[{"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/media?parent=2068"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/categories?post=2068"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/rumahpintar.co.id\/blog\/wp-json\/wp\/v2\/tags?post=2068"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}